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GuDViN [60]
3 years ago
11

How do you subtract fractions with different denominators?

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
6 0
You find a common denominator, for example, if you want to subtract 3/4 minus 1/2 you would have to multiply 1/2 by 2/2, which equals 2/4, then you can do 3/4-2/4, which is 1/4. Sorry if it’s a bit confusing, hope it helps!
klio [65]3 years ago
6 0

Answer:

When solving fractions with different denominators, you first need to make the denominators the same.

Example:

\frac{1}{2} -\frac{1}{4}

You need to make sure the denominators are the same.

Can 2 get multiply by something and will be 4?

The answer is yes, if you multiply 2 by 2, it will change the 2 to 4. You have to multiply the equation \frac{1}{2} by  \frac{4}{4} (which is also equivalent to 1) and which change the equation to \frac{2}{4}.

And now you can subtract because the denominators are the same.

Hope this helps!

If you have any questions feel free to ask.

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Answer:

h=20**

**The picture is not accurate for this problem.

Step-by-step explanation:

I would use Pythagorean Theorem to setup two equations since there are two triangles with no angle information.

Let BC=x+(99-x) where x is equal to the first partition of BC (reading from left to right) and (99-x) is equal to the second partition of BC (reading from left to right).

We have the following system to solve:

20^2=h^2+x^2

101^2=h^2+(99-x)^2

I will use elimination to first solve for x.

Subtract the equations:

20^2-101^2=x^2-(99-x)^2

Factor both sides using a^2-b^2=(a-b)(a+b):

(20-101)(20+101)=(x-(99-x))(x+(99-x))

Simplify inside the ( ).

(-81)(121)=(2x-99)(99)

Divide both sides by 9:

(-9)(121)=(2x-99)(11)

Divide both sides by 11:

(-9)(11)=(2x-99)(1)

Simplify both sides:

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Add 99 on both sides:

0=2x

Divide both sides by 2:

x=0

Now go to either equation we had in the beginning to find h.

20^2=h^2+x^2 with x=0

20^2=h^2

20=h

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