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3 years ago

How can I solve (x-8)^2

Mathematics

2 answers:

shusha [124]3 years ago

7 0

Answer:

x^2-16x+64

Step-by-step explanation:

Simplify= (x-8)(x-8)

Simplified= x^2-8x-8x+64

Combine like terms= x^2-16x+64

Basically whenever the sign is squared on the outside it's the equation times itself. Hope this helps.

devlian [24]3 years ago

6 0

Answer:

The answer is. x2-16x+64

Step-by-step explanation:

You have to simplify (x-8)(x-8)

X2-8x-8x+64

Combine like terms

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const2013 [10]

Answer:

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2 years ago

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3 years ago

What is the remainder of x^4-6x^3-10x^2+20x+15

sergejj [24]

Answer:

0 - 1

Step-by-step explanation:

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2 years ago

La ecuación de la recta que pasa por los puntos (2,-1) y (1,-5) es:

77julia77 [94]

Given:

A line passes through the points (2,-1) and (1,-5).

To find:

The equation of the line.

Solution:

If a line passes through the two points, then the equation of the line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

The line passes through the points (2,-1) and (1,-5). So, the equation of the line is

$y-(-1)=\dfrac{-5-(-1)}{1-2}(x-2)$

$y+1=\dfrac{-5+1}{-1}(x-2)$

$y+1=\dfrac{-4}{-1}(x-2)$

$y+1=4(x-2)$

Using distributive property, we get

$y+1=4(x)+4(-2)$

$y+1=4x-8$

Subtract 1 from both sides.

$y+1-1=4x-8-1$

$y=4x-9$

Therefore, the correct option is B.

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2 years ago

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Answer:

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2 years ago