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pochemuha
4 years ago
12

Karim's dog weighs 1.5 pounds less than double the weight to Frank's dog. Karim's dog weighs 15 pounds. Which equation and solut

ion can be used to find w, the weight of Frank's dog?

Mathematics
1 answer:
Radda [10]4 years ago
8 0
1. Because

info given:
Karim's dog = 15 pounds
Frank dog = 2x more pounds than Karim's dog + 1.5 pounds

(Karim) Equation 1: 15 = Frank
(Frank) Equation 2: 2w + 1.5

joining equation 1 and 2

15 = 2w + 1.5

Solve

15 - 1.5 = 2w
13.5 = 2w ÷ 2
w = 6.75
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A square has four sides which all have the same length.

So if we call the length of each side of the square 'a'

The sum of length of all the sides (the perimeter) will be ,

a + a + a + a = 4a

Now let's equal this to the perimeter to find the length of each side 'a'

4a\quad =\quad 8\\ \\ a\quad =\quad \frac { 8 }{ 4 } \\ \\ a\quad =\quad 2

So the length of each side of the square is 2 cm

To find area of a square we multiply the length of its two sides

So,

a\cdot a is the area of the square,

a\cdot a=\quad 2\cdot 2\quad =\quad 4\\ \\ 4\quad c{ m }^{ 2 }

The answer :

\boxed { 4\quad c{ m }^{ 2 } }
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4 years ago
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A color printer prints 23 pages in 9 minutes. How many pages does it print per minute? Round to the nearest hundredth. No links
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2.56

Step-by-step explanation:

To find out how many pages the printer prints per minute, you need to divide the amount of pages it printed with how long it printed.

So 23÷9

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Round 2.5555555 to the nearest hundredth you get 2.56.

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For the following, find the missing values.​
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Fine the midpoint of the line segment joining points A and B. A(4,-7); B(4,1)
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Midpoint: (4,-3)

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Rewrite the function by completing the square. 4x^2-4x+1=0
andrey2020 [161]

Do in <u>completing the square method.</u>

{4x}^{2}  - 4x + 1 = 0 \\ 4x^{2}-4x=-1  \\ \frac{4x^{2}-4x}{4}=\frac{-1}{4}  \\ x^{2}+\frac{-4}{4}x=\frac{-1}{4}  \\ x^{2}-x=\frac{-1}{4}  \\ x^{2}-x+\left(-\frac{1}{2}\right)^{2}=-\frac{1}{4}+\left(-\frac{1}{2}\right)^{2}  \\ x^{2}-x+\frac{1}{4}=\frac{-1+1}{4}  \\ x^{2}-x+\frac{1}{4}=0  \\ \left(x-\frac{1}{2}\right)^{2}=0  \\ \sqrt{\left(x-\frac{1}{2}\right)^{2}}=\sqrt{0}

Now simplify.

x-\frac{1}{2}=0 \\  x-\frac{1}{2}=0  \\  \\  \rightarrow \: x=\frac{1}{2}  \\  \rightarrow \: x=\frac{1}{2}

So, answer is..

\boxed{x=\frac{1}{2} }

Now <u>rewrite</u> the equation.

4 x ^ { 2 } - 4 x + 1 = 0 \\  \boxed{4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0  }

<u>Verification :-</u>

4 x ^ { 2 } - 4 x + 1 = 0 \\ 4\times \left(\frac{1}{4}\right)-4\times \left(\frac{1}{2}\right)+1=0  \\ 1-4\times \left(\frac{1}{2}\right)+1=0  \\ 1-\frac{4}{2}+1=0  \\ 1-2+1=0  \\ -1+1=0  \\ \underline{ 0 = 0} \:  \\  \dashrightarrow \text{true}

3 0
3 years ago
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