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Dafna11 [192]
3 years ago
9

Make a box and whiskers plot of the data. average temperature in Pittsburgh in June 79,70,73,84,83,88,75,72,76,68,68,79,84,74,75

,85,67,78,69,80
please help!!!

Mathematics
1 answer:
aliya0001 [1]3 years ago
7 0
The box-and-whisker plot is attached.

We first order the data from least to greatest:
67,68,68,69,70,72,73,74,75,75,76,78,79,79,80,83,84,85,85,88

Now we find the median.  Since there are 20 data values, the median is between 75 and 76:
(75+76)/2 = 151/2 = 75.5

Now we find the Lower Quartile (LQ).  We do this by finding the median of the lower half of data (from the median down).  There are 10 values here; the median is between 70 and 72:
(70+72)/2 = 142/2 = 71

Find the Upper Quartile (UQ).  Do this by finding the median of the upper half of data (from the median up).  There are 10 values here; the median is between 80 and 83:
(80+83)/2 = 163/2 = 81.5

The middle bar of the box is over the median.  The left hand side of the box is over LQ, and the right hand side of the box is over UQ.  Now we draw a whisker from the box to the highest value, 88, and from the box to the lowest value, 67.

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Rina8888 [55]
Area = length *width
A = x²
3x² = (x+10)(x+12)
3x² = x²+10x+12x+120
3x² = x²+22x+120
3x²-3x² = x²+22x+120-3x²
0 = -2x²+22x+120
Factor to solve for x: 
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(x+4)(x-15)
x = -4  & x = 15 but we can't have a negative length so we eliminate 4. The length of the square is 15 cm.
4 0
3 years ago
Which number line represents the solution to the inequality x - 3 > 2
Ivahew [28]

Answer: x > 5

Step-by-step explanation: To solve for <em>x</em> in this inequality, our goal is the same as it would be if this were an equation, to get x by itself on one side.

Since 3 is being subtracted from x, we add 3 to

both sides of the inequality to get x > 5.

When graphing x > 5, we have an open circle on 5 and the

open circle tells us that 5 is not part of our answer.

Then we draw an arrow going to the right to represent

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6 0
3 years ago
Solve each system by substitution: <br> 3x+y=2 <br> 4x+y=20<br> How do I solve this and set this up
Sholpan [36]
Solve the first equation for y.

3x+y=2

y=2-3x

Substitute

4x+(2-3x)=20

4x+2-3x=20

x=18
8 0
3 years ago
Read 2 more answers
Ayuda por favor
sergeinik [125]

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

<h3>¿Cómo determinar la medida de un lado de un triángulo desconocido?</h3>

En este problema tenemos un sistema formado por dos triángulos <em>similares</em>, la semejanza entre los dos triángulos se debe a la colinealidad entre los segmentos de línea AP' (triángulo <em>pequeño</em>) y AP'' (triángulo <em>grande</em>), así como de los lados AM y AB, así como los lados AN y AC, así como los <em>mismos</em> ángulos en la <em>misma</em> distribución. (Semejanza Lado - Ángulo - Lado)

En consecuencia, obtenemos las siguientes proporciones:

AP'/AP'' = MN/BC = 1/2     (1)

Finalmente, la proporción entre el triángulo AMN y el cuadrilátero BMNC es:

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)}{\frac{1}{2}\cdot (2\cdot a) \cdot  h - \frac{1}{2}\cdot a \cdot \left(\frac{1}{2}\cdot h \right)} = \frac{\frac{1}{4}\cdot a\cdot h }{a\cdot h - \frac{1}{4}\cdot a \cdot h }

\frac{AMN}{ABC - AMN} = \frac{\frac{1}{4} }{\frac{3}{4} } = \frac{1}{3}

A partir de la definición de razón y la teoría de semejanza entre triángulos, la razón del área del triángulo AMN y el área del cuadrilátero BMNC es equivalente a 1/3.

Para aprender sobre triángulos semejantes: brainly.com/question/21730013

#SPJ1

3 0
2 years ago
A warren of rabbits has a population of 25. The population is increasing at a rate of 20% per year. How can you write an exponen
KonstantinChe [14]

Answer:

f(x)= 25(1 + 0.20)^t

Step-by-step explanation:

The formula- <em>f(x)= a(1+r)^x</em>

<em />

a= initial amount (25)

r= growth rate (20%... 0.20)

x= # of times (we don't have that in here)

When you plug in the values, you get

f(x)= 25(1 + 0.20){t}

hope this helps!!

3 0
3 years ago
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