Ask question

Ask question

All categories

ICE Princess25 [194]

3 years ago

12

HEYY I REALLY NEED HELP WITH THIS QUESTION!!!!! d^3 = 12 D=?

2 answers:

swat323 years ago

6 0

Answer:

d³=12

d = cube rt 12

You can find cube root of 12 to get the value if d.

Thus d = 2.3 (rounded to nearest tenths)

Novay_Z [31]3 years ago

5 0

Answer:

4

Step-by-step explanation:

pls Mark my answer in brainlist and follow me

You might be interested in

Please solve :)))))))

ad-work [718]

Answer:

x=1

Step-by-step explanation:

We can solve this equation using a mix of simplifying and using arithmetic on both sides:

6-4x=7x-9x+4

6-4x=-2x+4

2-4x=-2x

2=2x

1=x

x=1

8 0

3 years ago

the foundation of a building is in the shape of a rectangle WITH THE LENGTH OF 20 METERS AND A WIDTH OF 18 METERS. TO THE NEARES

DerKrebs [107]

Answer:

Pythagoras theorem. 20^2 times 18^2 = distance^2

3 0

3 years ago

HELP ME YALLL PLEAseeee

Thepotemich [5.8K]

Answer:

Step-by-step explanation:

no

7 0

2 years ago

Solve for x: 6x + 1/4 (4x + 3) > 12<br> Ox><br> 10<br> 7<br> Ox> 2<br> ox= 10<br> X = 2

daser333 [38]

Given:

The inequality is:

$6x+\dfrac{1}{4}(4x+3)>12$

To find:

The values for x.

Solution:

We have,

$6x+\dfrac{1}{4}(4x+3)>12$

Using distributive property, we get

$6x+\dfrac{1}{4}(4x)+\dfrac{1}{4}(3)>12$

$6x+x+\dfrac{3}{4}>12$

$7x>12-\dfrac{3}{4}$

$7x>\dfrac{48-3}{4}$

On further simplification, we get

$7x>\dfrac{45}{4}$

Divide both sides by 7.

$x>\dfrac{45}{7\times 4}$

$x>\dfrac{45}{28}$

Therefore, the required solution is $x>\dfrac{45}{28}$ .

Note: All options are incorrect.

7 0

3 years ago

What's the largest fraction in eaxh group? a. 5/6 and 29/36 b. 5/12 and 3/8 c.2/5 and 19/45 d.5/7, 13/14, and 19/21

Sever21 [200]

Answer:

a) $\frac{5}{6}$ is greatest fraction.

b) $\frac{5}{12}$ is greatest fraction.

c) $\frac{19}{45}$ is greatest fraction.

d) $\frac{13}{14}$ is greatest fraction.

Solution:

To compare two fraction we need to make denominator of both the fraction same.

a)Given fraction are $\frac{5}{6}$ and $\frac{29}{36}$

$\frac{5}{6}=\frac{5 \times 6}{6 \times 6}=\frac{30}{36}$

So $\frac{30}{36}$ is equivalent to $\frac{5}{6}$

So $\frac{30}{36}>\frac{5}{6}$

Hence $\frac{30}{36}$ that is $\frac{5}{6}$ is greater than $\frac{29}{36}$

b)Given fraction are $\frac{5}{12}$ and $\frac{3}{8}$

$\frac{5}{12}=\frac{5 \times 2}{12 \times 2}=\frac{10}{24}$

Similarly we get $\frac{3}{8}=\frac{3 \times 3}{8 \times 3}=\frac{9}{24}$

So $\frac{10}{24}>\frac{9}{24}$

$\frac{10}{24}>\frac{9}{24}$

That is $\frac{5}{12}>\frac{3}{8}$

Hence $\frac{5}{12}$ is greater than $\frac{3}{8}$

c) Given fraction are $\frac{2}{5}$ and $\frac{19}{45}$

$\frac{2}{5}=\frac{2 \times 9}{5 \times 9}=\frac{18}{45}$

So $\frac{19}{45}>\frac{18}{45}$

That is $\frac{19}{45}>\frac{2}{5}$

Hence $\frac{19}{45}$ is greater than $\frac{2}{5}$

d)Given fraction are $\frac{5}{7}$ , $\frac{13}{14}$ and $\frac{19}{21}$

$\frac{5}{7}=\frac{5 \times 6}{7 \times 6}=\frac{30}{42}$

$\frac{13}{14}=\frac{13 \times 3}{14 \times 3}=\frac{39}{42}$

Similarly we get

$\frac{19}{21}=\frac{19 \times 2}{21 \times 2}=\frac{38}{42}$

So $\frac{39}{42}>\frac{38}{42}>\frac{30}{42}$

That is $\frac{13}{14}>\frac{19}{21}>\frac{5}{7}$

Hence $\frac{13}{14}$ is greatest fraction.

4 0

3 years ago