Answer:
79.9 ft
Solution,
Let AB is the Building and MA is Boy's height.
Suppose BC = X feet
In ∆MBC
![tan \: 53 = \frac{ma + ab}{bc} \\ tan \: 53 = \frac{106}{x} \\ tan \: 53 \times x = 106 \\ x = \frac{106}{tan \: 53} \\ x = 79.9 \: ft](https://tex.z-dn.net/?f=tan%20%5C%3A%2053%20%3D%20%20%5Cfrac%7Bma%20%2B%20ab%7D%7Bbc%7D%20%20%5C%5C%20tan%20%5C%3A%2053%20%3D%20%20%5Cfrac%7B106%7D%7Bx%7D%20%20%5C%5C%20tan%20%5C%3A%2053%20%5Ctimes%20x%20%3D%20106%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B106%7D%7Btan%20%5C%3A%2053%7D%20%20%5C%5C%20x%20%3D%2079.9%20%5C%3A%20ft)
Hope this helps...
Good luck on your assignment...
You can count from 34-28 and the numbers you counted (the numbers in between 34-28) is your answer.
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Answer: On the interval [25, 30] the function y = cos x is at it's minimum at x = 9pi or about 28.26.
The graph of y = cos x starts at 1 and moves in the shape of a wave from -1 to 1. It reaches it's first minimum value when x = pi. The period of the wave is 2 pi.
Therefore, it is at its lowest value at the following values, 1pi, 3pi, 5pi, 7pi, 9pi... The value in our given interval is 9pi.