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Evgesh-ka [11]
3 years ago
5

Simplify square root of five times the quantity six minus four square root of three.

Mathematics
2 answers:
katovenus [111]3 years ago
7 0

Answer:

C

6\sqrt{x} 5-4\sqrt{x} 15

Sphinxa [80]3 years ago
4 0

Answer:

6√5 - 4√3

Step-by-step explanation:

The question ask us to simplify the square root of 5 times the quantity 6 minus 4 square root of 3 . The word expression can be represented mathematically as follows:

√5 × 6 - 4√3 . The expression forms a Surd.

√5 × 6 - 4√3

6√5 - 4√3

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vampirchik [111]
Answer: The p(success) = 0.6

Your question is a little unclear, but I believe you are asking about the probability that at least one of the trials in the experiment were successful.

If that is the case, you simply have to add the probability of 1 success with the probability of 2 successes.

That is 0.48 +  0.16 = 0.64

Rounding our answer to one decimal place gives us 0.6.
7 0
2 years ago
Read 2 more answers
A boat traveled 36 miles in 1.5 hours and then 14 miles in 0.75 hours. what is the average speed of the boat?
jeka57 [31]
Speed=distance/time
You'll have to combine like terms.
36+14=50
1.5+0.75=2.25

And then you can use the formula.
50/2.25

7 0
3 years ago
Find the arc measures and angles listed below.
rusak2 [61]

Answer if you divide them or x them you'll get the answer!

4 0
2 years ago
Mr Smith's art class took a bus trip to an art museum. The bus averaged 65 miles per hour on the highway and 25 miles per hour i
Leya [2.2K]
Let x be the distance traveled on the highway and y the distance traveled in the city, so:
\left \{ {{x+y=375} \atop { \frac{1}{65}x+ \frac{1}{25}y =7}} \right.
 
Now, the system of equations in matrix form will be:
\left[\begin{array}{ccc}1&1&\\ \frac{1}{65} & \frac{1}{25} &\end{array}\right]   \left[\begin{array}{ccc}x&\\y&\end{array}\right] =  \left[\begin{array}{ccc}375&\\7&\end{array}\right]

Next, we are going to find the determinant:
D=  \left[\begin{array}{ccc}1&1\\ \frac{1}{65} & \frac{1}{25} \end{array}\right] =(1)( \frac{1}{25}) - (1)( \frac{1}{65} )= \frac{8}{325}
Next, we are going to find the determinant of x:
D_{x} =  \left[\begin{array}{ccc}375&1\\7& \frac{1}{25} \end{array}\right] = (375)( \frac{1}{25} )-(1)(7)=8

Now, we can find x:
x=  \frac{ D_{x} }{D} = \frac{8}{ \frac{8}{325} } =325mi

Now that we know the value of x, we can find y:
y=375-325=50mi

Remember that time equals distance over velocity; therefore, the time on the highway will be:
t_{h} = \frac{325}{65} =5hours
An the time on the city will be:
t_{c} = \frac{50}{25} =2hours

We can conclude that the bus was five hours on the highway and two hours in the city. 

8 0
3 years ago
How can this 12×2+2³ make 120
Alex17521 [72]

Step-by-step explanation:

12\times(2+2^3)\qquad\text{use PEMDAS}\\\\\text{first power}\\\\=12\times(2+8)\\\\\text{next addition in parentheses}\\\\=12\times10=120

8 0
2 years ago
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