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3 years ago

5

Simplify square root of five times the quantity six minus four square root of three.

2 answers:

katovenus [111]3 years ago

7 0

Answer:

C

$6\sqrt{x} 5-4\sqrt{x} 15$

Sphinxa [80]3 years ago

4 0

Answer:

6√5 - 4√3

Step-by-step explanation:

The question ask us to simplify the square root of 5 times the quantity 6 minus 4 square root of 3 . The word expression can be represented mathematically as follows:

√5 × 6 - 4√3 . The expression forms a Surd.

√5 × 6 - 4√3

6√5 - 4√3

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Evaluate this integral. I'm not sure how to evaluate integrals with absolute values.

SOVA2 [1]

Answer:

1

Step-by-step explanation:

The first step is to understand what the integrand looks like. (See the graph below.)

It is -1 for x < 0 and +1 for x > 0. Thus, the value of this integral is ...

$\int\limits^0_{-1} {-1} \, dx + \int\limits^2_0 {1} \, dx=-1+2=1$

_____

Essentially, you treat the absolute value as a piecewise linear function. This is the same way you treat an absolute value in any equation or inequality.

Here, this means you divide the integral into two parts: one where the integrand is -x/x, and one where it is +x/x.

6 0

3 years ago

What is the product of 1 2/3 and -3 1/2

natulia [17]

Answer:

-5 5/6

Step-by-step explanation:

1 2/3=5/3

-3 1/2=-7/2

5/3*-7/2=-35/6= -5 5/6

6 0

2 years ago

Read 2 more answers

Question 4 of 25

natali 33 [55]

Answer:

b

Step-by-step explanation:

3 0

3 years ago

masha68 [24]

Answer:

51.9 cm²

Step-by-step explanation:

From the diagram attached,

Area of the white region(segment)(A) = Area minor sector- area of the triangle

A = (πr²∅/360°)-(1/2r²sin∅)............... Equation 1

Where r = radius of the circle, Ф = reflex angle formed at the center of the circle, π = pie

From the question,

Given: r = 7 cm, Ф = 150°

Constant: π = 22/7

Substitute these values into equation 1

A = [(22/7)×7²×150/360]-[(1/2)×7²×sin150]

A = 64.17-12.25

A = 51.92

A = 51.9 cm²

5 0

2 years ago

Plz hurry!!!! thank you!!!!

RoseWind [281]

Answer:

$m\angle KLM=53.13^o$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of angle KOM

In the triangle KOM

we have

$KO=MO=r=5\ units$

$KM=8\ units$

Applying the law of cosines

$8^2=5^2+5^2-2(5)(5)cos(KOM)$

$64=50-50cos(KOM)$

$50cos(KOM)=50-64$

$50cos(KOM)=-14$

$cos(KOM)=-14/50$

$m\angle KOM=cos^{-1}(-14/50)$

$m\angle KOM=106.26^o$

step 2

Find the measure of the arc KM

we know that

$arc\ KM=m\angle KOM$ ----> by central angle

we have

$m\angle KOM=106.26^o$

so

$arc\ KM=106.26^o$

step 3

Find the measure of angle KLM

we know that

The inscribed angle is half that of the arc comprising

$m\angle KLM=\frac{1}{2}[arc\ KM]$

we have

$arc\ KM=106.26^o$

substitute

$m\angle KLM=\frac{1}{2}[106.26^o]$

$m\angle KLM=53.13^o$

7 0

3 years ago