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hoa [83]
3 years ago
13

Combine like terms -2/3p + 1/5 - 1 + 5/6p

Mathematics
1 answer:
Bezzdna [24]3 years ago
5 0
1/6p - 4/5

Explanation: -2/3p needs to have the same denominator as 5/6p so they can combine. (Note, whatever sign is in front of a number determines if it is negative or positive. Your equation indicates that the bolded parts are negative and the other parts are positive: -2/3p + 1/5 - 1 + 5/6p. So what we are really doing in an equation like this is combining some numbers together)
-2/3p and 5/6p and the least common multiple of six, so we adjust the numbers to each have a denominator of 6. 5/6p is already there, so we need to adjust -2/3p.
We can multiply both the numerator and denominator by 2 to turn -2/3p into -4/6p. -4/6p has the same value as -2/3p, and now it also has the same denominator as 5/6p!
We then have to combine like terms, therefore combining -4/6p with 5/6p. When adding together fractions, the denominator does not change (this is why both numbers must have the same denominators). So our answer will be _/6p. So we combine -4 with 5, giving us one.
Therefore, -2/3p combined with 5/6p is 1/6p.
Now we have to combine our other set of like terms, 1/5 and -1. We can do this the same way that we combined the other numbers.
1/5 and -1 need the same denominator. This is simple because 1 can easily be figured out with any denominator, as long as the numerator and denominator are the same. This would make 1 = 5/5. But we need it negative, so it would be -5/5.
Now that we have common denominators, we can combine!
1/5 - 5/5
Remember what we said before, the solution will have the same denominator, so all we need to do is (in this case) subtract the numerators.
1 - 5 = 4
So that would be -4/5.
With the like terms combined, we just need to put our two combinations (1/6p and -4/5) together!

Our answer: 1/6p - 4/5

I hope that helps!
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Your answer is 23.31538291 feet.

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2 years ago
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I’ll give u brainiest pls help me im so lost
Vlad1618 [11]

Answer:

(f o g)(4)=27

Step-by-step explanation:

(f o g)(4)=2x+5

f(g(4))=2x+5

f(4²-2(4)+3)=2x+5

f(16-8+3)=2x+5

f(8+3)=2x+5

f(11)=2x+5

f(11)=2(11)+5

f(11)=22+5

f(11)=27

Therefore, (f o g)(4)=27

3 0
3 years ago
Four times the amount of money in my bank account plus $200 is still two
ioda

Answer:

$700

Step-by-step explanation:

So, I like to extract the information we know and form it into an equation.

So we know that after multiplying what you have in the bank by 4, then add 200 dollars you get two thousand dollars less than a fourth of what's in your dad's bank account.

Your dad has $20,000 in the bank.

Before we write the equation let's find what two thousand less than a fourth of 20,000 is.

20,000/4 = 5,000

Now, 5,000 - 2,000 = 3,000

Ok let's say x is how much money you have

So:

4x + 200 = 3,000

we can isolate the variable by subtracting 200 from both sides

4x = 2,800

then we can divide by 4 on each side

x = 700

so you have $700 in the bank

4 0
3 years ago
Use the identity below to complete the tasks:
Gennadij [26K]

Answer:

a3+b3=(a+b)(a2-ab+b2)

4 0
3 years ago
Find the value of A if the 4-digit number 3A5A is divisible by both 3 and 5.
Arturiano [62]

Answer:

The value of A is 5

Step-by-step explanation:

- The number is divisible by 3 if the sum of its digits is a number

  divisible by 3

- Ex: 126 is divisible by 3 because the sum of its digits = 1 + 2 + 3 = 6

  and 6 is divisible by 3

- The number is divisible by 5 if its ones digit is zero or 5

- Ex: 675 is divisible by 5 because its ones digit is 5

        890 is divisible by 5 because its ones digit is 0

- We are looking for the value of A in the 4-digit number 3A5A which

  makes the number divisible by both 3 and 5

∵ A is in the ones position

∴ A must be zero or 5

- Let us try A = 0

∵ A = 0

∴ The number is 3050

∵ The sum of the digits of the number = 3 + 0 + 5 + 0 = 8

∵ 8 is not divisible by 3

∴ 3050 is not divisible by both 3 and 5

∴ A can not be zero

- Let us try A = 5

∵ A = 5

∴ The number is 3555

∵ The sum of the digits of the number = 3 + 5 + 5 + 5 = 18

∵ 18 is divisible by 3

∴ 3555 is divisible by both 3 and 5

∴ A must be equal 5

* <em>The value of A is 5</em>

5 0
3 years ago
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