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3 years ago

Factor the GCF: -6x^4y^5 - 15x^3y^2 + 9x^2y^3

1 answer:

5 0

<span>-6x^4y^5 - 15x^3y^2 + 9x^2y^3

</span>-6x^4y^5 = -2, 3, x, x, x, x, y, y, y, y, y
15x^3y^2 = -5, 3 x, x, x, y, y
9x^2y^3 = 3, 3 x, x, y, y, y

Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2

Divide that out and we get
$\frac{-6x^4y^5 - 15x^3y^2 + 9x^2y^3}{-3x^2y^2} =$
$2x^2y^3 + 5x - 3y$
$-3x^2y^2(2x^2y^3 + 5x - 3y)$

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$12C5 *(12C3) = 792*220 =174240 ways$

Step-by-step explanation:

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Step-by-step explanation:

Step 1:

Let P(G) represent the probability of girls team getting a game and P(B) represent the probability of the boys team getting a game.

P(B ∪ G) represents the probability of either girls and boys team getting a game.

P(B ∩ G) represents the probability of both girls and boys team getting a game.

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It is given that P(G) = 0.8, P(B) = 0.7 and P(B ∩ G) = 0.65

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Step 3:

P(B ∪ G) = P(B) + P(G) - P(B ∩ G)

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