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Slav-nsk [51]
3 years ago
6

Factor the GCF: -6x^4y^5 - 15x^3y^2 + 9x^2y^3

Mathematics
1 answer:
natta225 [31]3 years ago
5 0
<span>-6x^4y^5 - 15x^3y^2 + 9x^2y^3

</span>-6x^4y^5 =  -2, 3, x, x, x, x,  y, y, y, y, y
15x^3y^2 =  -5, 3 x, x, x, y, y
9x^2y^3 =    3, 3 x, x, y, y, y

Each group has a 3 in common and each group has 2 x in common and each group has 2 y in common so the GCF = -3x^2y^2

Divide that out and we get 
\frac{-6x^4y^5 - 15x^3y^2 + 9x^2y^3}{-3x^2y^2} =
2x^2y^3 + 5x - 3y
-3x^2y^2(2x^2y^3 + 5x - 3y)

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