The object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
<h3>What is the distance?</h3>
Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.
It is given that:
An object is traveling at a steady speed of 10 1/5 mi/h.
u = 10 1/5 min/h
u = 51/5 min/h
As we know, the speed-distance relationship:
time = distance/speed
distance = 1 4/5 = 9/5
time = (9/5)/(51/5)
time = 9/51 hours
time = (9/51)60
time = 10.58 minutes
Thus, the object needs 10.58 minutes to travel 1 4/5 if the object is traveling at a steady speed of 10 1/5 mi/h.
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Answer:
Shorter leg = 2.5 ft.
Longer leg = 6.5 ft.
Step-by-step explanation:
a^2 + b^2 = c^2
Because the hypotenuse = 7 ft, a^2 + b^2 = 49
To represent the two legs, we can use x and x+4.
x^2 + (x+4)^2 = 49
Simplifying this equation using FOIL gives us 2x^2 + 8x - 33 = 0.
Then, using the quadratic formula, we find that x = 2.5.
Thus, the shorter leg is 2.5 ft. and, when 4 is added, the longer leg is 6.5 ft.
The answer is 350 dollars Explanation 350-(350X0.4) is 210
Answer:
A - (1,2) (2,6)
B - 3.5
C - I don't know... Sorry
D - At least 3.5
E - (5,6) (1,2)
Step-by-step explanation:
