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lys-0071 [83]
3 years ago
11

Larry invests $100 in a savings plan. The plan pays 4 1/2 % interest each year on his $100 account balance.

Mathematics
1 answer:
son4ous [18]3 years ago
5 0

Answer:

$14.12 (after 3 years) and $24.62 (after 5 years)

Step-by-step explanation:

Use the compound amount formula (assuming annual compounding):

A = P(1 + r)^t

Here  A = $100(1 + 0.045)^3 (after 3 years)

             = $100(1.045)^3 = $114.12.  

          The interest earned (alone) would be $14.12.

After 5 years:

Here  A = $100(1 + 0.045)^5 (after 5 years)

             = $100(1.045)^5 = $124.62

          The interest earned (alone) would be $24.62.

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Answer:

A line of best fit is a straight line that best represents the data on a scatter plot. This line may pass through some of the points, none of the points, or all of the points. A real world example would be a scatter plot of the number if balloons bought each year and a straight line going diagonally representing the average or goal of the number of balloons bought. The points may be above (signaling that the number of balloons purchased was higher than normal or exceeded the goal) or they may be below (signaling that balloon sales are lower than normal or didnt meet there goals). I hope this helps, if not then I apologize

3 0
3 years ago
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Jenny’s Gift Shop sells candles in a variety of packages. The cost per candle is the same in every package. A package of 8 candl
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Answer:

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4 0
2 years ago
An estimated regression equation that was fit to estimate ductility in steel using its carbon content was found to be significan
AnnZ [28]

Answer:

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

Step-by-step explanation:

Hello!

Considering the dependent variable:

Y: Ductility in steel.

And the independent variable:

X: Carbon content of the steel.

The linear regression was estimated and a prediction interval was calculated.

The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=x_{0}]

In this case 95% prediction interval for Y/X=0.5

At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.

I hope it helps!

6 0
3 years ago
Kelly needs to order lunch for orders 6 people at a business meeting. Her menu choices are chicken salad for a cost of $5 per pe
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Answer:

She would be able to buy

4 Chicken Salads &

2 Egg Salads

Step-by-step explanation:

4x5=20

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2x4=8

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