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marishachu [46]
2 years ago
13

Yolanda is saving money to buy a game. so far she has saved $30 , which is five-sixths of the total cost of the game. how much d

oes the game cost?
Mathematics
1 answer:
inna [77]2 years ago
4 0
A trick is to replace the "of" with a multiplication symbol"
the 30 dollar is (5/6 of the total cost =>30=(5/6)*c =>c=30*(6/5)=36
the game cost 36 dollars
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A3-b3=(a-b)(a2+an+b2) 64x6-27
olga nikolaevna [1]
<span>a³-b³=(a-b)(a²+ab+b²)

64x⁶ - 27

64 = 4³, 
x⁶ = (x²)³
27 = 3³

</span>64x⁶ - 27 = 4³(x²)³ -3³ = (4x²)³ -3³.  Now, we can use a formula where a=4x², b=3

(4x²)³ -3³ = (4x² -3)((4x²)² +4x²*3 + 3²) =  (4x² -3)(16x⁴ +12x² + 9) 
<span>
Answer: </span>64x⁶ - 27=  (4x² -3)(16x⁴ +12x² + 9) <span>

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3 years ago
Find the outlier in the set of data.(
Ksivusya [100]
The answer is A (38)
5 0
3 years ago
Given f(x)=3^x-8, what is<br> the value of f(10)
Westkost [7]

Answer:

f(x) =  {3}^{(x)}  - 8 \\ f(10) =  {3}^{(10)} - 8  \\  = 59041

8 0
2 years ago
which has greater cenetic energy a car traveling 30.0 km/hr or one twice as heavy traveling at 15 km/hr?​
iVinArrow [24]

Answer:

30 km/h car

Step-by-step explanation:

From analysis the   car traveling at 30 km/h has greater kinetic energy

we can deduce it from the expression of kinetic energy which is

KE=\frac{1}{2} mv^2

Assuming the mass m= 1 kg

 

For the 30 km/h

KE=\frac{1}{2}*1*30^2 \\\\KE=\frac{1}{2}*1*900\\\\\KE=450 J

   

For the 15 km/h

KE=\frac{1}{2}*2*15^2 \\\\ KE=\frac{1}{2}*2*225 \\\\\ KE=\frac{1}{2}*450 J\\\\\ KE=225 J

Though the kinetic energy is a function of mass and velocity, but from our analysis the faster moving object has more KE

8 0
3 years ago
1. Una escalera de 4 m de longitud se apoya sobre una pared vertical. Si la distancia entre la base de la escalera a la pared es
enot [183]

Answer:

puedes resolver de dos maneras si diste teorema de Pitágoras lo aplicas

hipotenusa al cuadrado = cateto 2 +cateto 2 ( el 2 significa al cuadrado)

sustituyes

hipotenusa= 4m

cateto= 2,5

hay que hallar el otro cateto que nos daría la altura a la que está la escalera

despejamos y tenemos

cateto 2= hip2 -cat2

cat2=(4)2-(2,5)2=

       =   16-6,25=9,75

luego hallamos la raíz cuadrada de 9,75= 3,12

     

la altura a la que se encuentra es 3,12m

-si aun no diste Pitágoras podes representarlo en una hoja utilizando cm en lugar de metros( a escala). trazas el triángulo rectángulo la base te la da la distancia a la cual se encuentra la escalera de la pared es decir 2,5cm trazas la hipotenusa de 4cm de manera que coincida con el cateto opuesto , y mides el valor de este ,será de 3,12cm no olvides que la respuesta la debes dar en metros ya que es la unidad de medida que te da.

4 0
2 years ago
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