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erastovalidia [21]
3 years ago
10

Please help me please will give brainliest

Mathematics
2 answers:
adoni [48]3 years ago
6 0

Answer:

a

Step-by-step explanation:

Ksivusya [100]3 years ago
4 0

Answer:

A. less than three batteries were used in five hours.

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Tony collected data on years of employment and the annual salaries of the sales people at Company Z. He made a scatter plot and
devlian [24]
Can you send a picture?
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3 years ago
F(x) = 2x² + x at (-1, 1)
lord [1]

Answer:

f(x) = 2 {x}^{2}  + x \\ at \: that \: point \: given \:  \: x =  - 1 \\ f(x) = 2 {( - 1)}^{2}  + ( - 1) \\ f(x) = 2 - 1 \\ f(x) = 1

4 0
3 years ago
Helppppppppppppppppp lol
asambeis [7]

Answer:

There are no solutions.

Step-by-step explanation:

If there is 74 and 54 but with the same 15x: there is no solution. Even with negative.

3 0
3 years ago
Read 2 more answers
The probability that a randomly selected 2 2​-year-old male garter snake garter snake will live to be 3 3 years old is 0.98861 0
Mnenie [13.5K]

Answer:

a. Probability = 0.97735

b. Probability = 0.92294

c. P(At\ Least\ One) = 1

No, it is not unusual if at least 1 lives up to 3.

Step-by-step explanation:

Given

Represent the probability that a 2 year old snake will live to 3 with P(Live);

P(Live) = 0.98861

Solving (a): Probability that two selected will live to 3 years.

Both snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)\ and\ P(Live)

Probability = 0.98861 * 0.98861

Probability = 0.9773497321

Probability = 0.97735 <em>--- Approximated</em>

Solving (b): Probability that seven selected will live to 3 years.

All 7 snakes have a chance of 0.98861 to live up to 3 years.

So, the required probability is:

Probability = P(Live)^n

Where n = 7

Probability = 0.98861^7

Probability = 0.92294324145

Probability = 0.92294 <em>--- Approximated</em>

Solving (c): Probability that at least one of seven selected will not live to 3 years.

In probabilities, the following relationship exist:

P(At\ Least\ One) = 1 - P(None).

So, first we need to calculate the probability that none of the 7 lived up to 3.

If the probability that one lived up to 3 years is 0.98861, then the probability than one do not live up to 3 years is 1 - 0.98861

This gives:

P(Not\ Live) = 0.01139

The probability that none of the 7 lives up to 3 is:

P(None) = P(Not\ Live)^7

P(None) = 0.01139^7

Substitute this value for P(None) in

P(At\ Least\ One) = 1 - P(None).

P(At\ Least\ One) = 1 - 0.01139^7

P(At\ Least\ One) = 0.99999999999997513055642436060443621

P(At\ Least\ One) = 1 ---- Approximated

No, it is not unusual if at least 1 lives up to 3.

This is so because the above results, which is 1 shows that it is very likely for at least one of the seven to live up to 3 years

7 0
3 years ago
Write an expression for the model. Find the sum. options: a) 2 + (–3); 1 b) –3 + 2; 5 c) 2 + 3; 5 d) 2 + (–3); –1
Dima020 [189]

Answer:

c) 2 + 3 = 5                   TRUE

d) 2 + (–3) = -1              True

Step-by-step explanation:

When adding integers (positive and negative whole numbers), there are three cases:

  • Positive and positive increases and sum is positive. Ex. 4 + 6 = 10
  • Positive and negative where you subtract and take the sign of the larger number. Ex. 3 + -8 = -5 or -3 + 8 = 5
  • Negative and negative decrease and the sum if negative. Ex. -4 + -6 = -10.

Use these rules to simplify each expression.

a) 2 + (–3) = -1 not 1     FALSE

b) –3 + 2 = -1 not 5      FALSE

c) 2 + 3 = 5                   TRUE

d) 2 + (–3) = -1              True

5 0
4 years ago
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