Question

The length of a rectangle is (x + 1) cm and its width is 5cm less than its length.

Answer 1

Answer:

a) the area of a square is in terms of x is

$(x+1)^2$ centimeter square

b)The length of the rectangle is l = (x+1)

                                       l = 7+1 =8 cm

The width of the rectangle is w = [(x+1)-5]

                                     w = (7+1)-5 =3 cm

Step-by-step explanation:

a) the area of a square is in terms of x is

 area of square is $l^{2} = (x+1)(x+1)$

                                 = $(x+1)^2$

b)  Given length is  l = (x+1) cm and

the width is 5 cm less than its length.

so we have take width is w = (x+1)-5 cm

Given area of triangle is  24 cm

Area of rectangle = length X width

24  =  (x+1)(x+1 -5 )

now simplification $24 = (x+1)^2 - 5 (x+1)$

apply (a+b)^2 = a^2+2 a b+b^2

$x^2+2 x+1-5 x-5 =24$

$x^2 -3 x -4-24=0$

$x^{2} -3 x -28 =0$

now find factors of 28  = 7 X 4 is  

$x^{2} -7 x+4 x-28=0$

$x(x-7)+4(x-7)=0$

$(x+4)(x-7)=0$

x = -4 and x=7

there fore you have to choose x = 7

The length of the rectangle is l = (x+1)

                                       l = 7+1 =8

The width of the rectangle is w = [(x+1)-5]

                                     w = (7+1)-5 = 3

Verification:-

Given area of rectangle  = 24 = 8 X 3

                                           24 =24

so we can not choose x=-4

we have to choose x =7 only