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3 years ago

What is the value of x in the equation 7x+2v =48 when y =3

Mathematics

2 answers:

Phantasy [73]3 years ago

4 0

Answer:

3 3/7

Step-by-step explanation:

7x+2v=48

2v. -2

-------

7x+46=48

-46. -46

---------------------

7x=2/7. x=2/7=1/7

x=1/7

bonufazy [111]3 years ago

4 0

Answer:

x = 6

Step-by-step explanation:

7x+2y =48 when y =3

Substitute for y in the equation.

7x + 2(3) = 48

7x + 6 = 48

7x = 48 - 6

7x = 42

x = 42/7

x = 6

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Not sure what to do here? Naomi has 50 red beads and white beads. The number of red beads is 1 more than 6 times the number of w

lorasvet [3.4K]

R + w = 50
r = 6w + 1

now we sub ..
6w + 1 + w = 50
7w + 1 = 50
7w = 50 - 1
7w = 49
w = 49/7
w = 7 <== white beads

r = 6w + 1
r = 6(7) + 1
r = 42 + 1
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3 years ago

furniture maker used 1/2 of a can of paint to paint some chairs. She used 1/6 of a can of paint for each chair. How many chairs

dezoksy [38]

Answer:

3 chairs

Step-by-step explanation:

1/2 is the same as 3/6

There are three 1/6 in 3/6.

(3/6) ÷ (1/6) = 3

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2 years ago

D/d{cosec^-1(1+x²/2x)} is equal to

SIZIF [17.4K]

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

Let assume that

$\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

We know,

$\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}$

So, using this, we get

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)$

Now, we use Method of Substitution, So we substitute

$\red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}$

So, above expression can be rewritten as

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)$

$\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)$

$\rm\implies \:y = 2z$

$\bf\implies \:y = 2 {tan}^{ - 1}x$

So,

$\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x$

Thus,

$\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)$

$\rm \: = \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)$

$\rm \: = \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)$

$\rm \: = \: 2 \times \dfrac{1}{1 + {x}^{2} }$

$\rm \: = \: \dfrac{2}{1 + {x}^{2} }$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}$

Hence, Option (d) is correct.

6 0

2 years ago

What is the value of x in the equation 7x+2v =48 when y =3​

What is the value of x in the equation 7x+2v =48 when y =3