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kipiarov [429]
3 years ago
11

A chemist weighed out 101. g of potassium. Calculate the number of moles of potassium she weighed out.

Mathematics
2 answers:
ehidna [41]3 years ago
6 0
 The answer is 2.58 moles potassium<span>
The solution to this is,
to find moles, convert grams to mole by the equation
grams(mole/gram)=moles
101. g of potassium(1 mole potassium/</span><span>39.10 g potassium)=2.58 moles potassium</span>
Bumek [7]3 years ago
5 0

Answer:

101 g of Potassium is equivalent to 2.583 moles of Potassium.

Step-by-step explanation:

As per definition of moles, molecular weight of a substance = 1 mole

So molecular weight of Potassium = 39.0983 g

∵ 39.0983 g weight of Potassium = 1 mole

∴ 1 g weight of Potassium = \frac{1}{39.0983} g

∴ 101 g of Potassium = \frac{101}{39.0983} g

                                  = 2.583 moles

Therefore, 101 g of Potassium is equivalent to 2.583 moles of Potassium.

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Divide distance by time:

10.5 inches / 3 seconds = 3.5 inches per second

Answer: 3.5 inches per second

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What is the value of the expression below when y 8 and z = 8? 9y + 3z​
aleksley [76]

Answer:

96

Step-by-step explanation:

8y+3z

9(8)+3(8)

72+24

96

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3 years ago
Write 0.6 as a fraction ?
satela [25.4K]

Answer:

6/10 ; 3/5 (simplified form)

Step-by-step explanation:

To solve, note the decimal place value. Move the decimal point to the right two place values, and set it over 100

0.6 = 60/100

Simplify the fraction. Divide common factors from the numerator & denominator (20 in this case)

(60/100)/(20/20) = 3/5

3/5 is your answer

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3 years ago
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A bridge in the shape of an arch connects two cities separated by a river. The two ends of the bridge are located at (–7, –13) a
sdas [7]

Answer:

y=-\dfrac{13}{49}x^2

Step-by-step explanation:

The shape of an arch corresponds to a parabola.

the general equation for a parabola is:

y=ax^2+bx+c

we're given three coordinates: (-7,-13),(7,-13) and (0,0)

so we can plug these values in the general equation to make 3 separate equations:

(x,y) = (-7,-13)

-13=a(-7)^2+b(-7)+c

49a-7b+c=-13

(x,y) = (7,-13)

-13=a(7)^2+b(7)+c

49a+7b+c=-13

(x,y) = (0,0)

0=a(0)^2+b(7)+c

c=0

so we have three equations. and we can solve them simultaneously to find the values of a,b, and c.

we've already found c = 0, let's use substitute it to other equations.

49a-7b+c=-13\quad\Rightarrow\quad49a-7b=-13

49a+7b+c=-13\quad\Rightarrow\quad49a+7b=-13

we can solve these two equation using the elimination method, by simply adding the two equations

\quad\quad49a-7b=-13\\+\quad49a+7b=-13

------------------------------

\quad\quad 98a=-26

\quad\quad a=-\dfrac{13}{49}

Now we can plug this value of a in any of the two equations.

49a-7b=-13

49\left(-\dfrac{13}{49}\right)-7b=-13

-13-7b=-13

-7b=0

b=0

We have the values of a,b, and c. We can plug them in the general equation to find the equation of the arch.

y=\left(-\dfrac{13}{49}\right)x^2+0x+0

y=-\dfrac{13}{49}x^2

49y=-13x^2

This our equation of the arch!

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3 years ago
A share of stock dropped 6 points on Tuesday. On Wensday, the same stock gained 3 points. What was the total loss for the two da
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The answer is three (3)
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