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3 years ago

A chemist weighed out 101. g of potassium. Calculate the number of moles of potassium she weighed out.

2 answers:

6 0

The answer is 2.58 moles potassium
The solution to this is,
to find moles, convert grams to mole by the equation
grams(mole/gram)=moles
101. g of potassium(1 mole potassium/39.10 g potassium)=2.58 moles potassium

Bumek [7]3 years ago

5 0

Answer:

101 g of Potassium is equivalent to 2.583 moles of Potassium.

Step-by-step explanation:

As per definition of moles, molecular weight of a substance = 1 mole

So molecular weight of Potassium = 39.0983 g

∵ 39.0983 g weight of Potassium = 1 mole

∴ 1 g weight of Potassium = $\frac{1}{39.0983}$ g

∴ 101 g of Potassium = $\frac{101}{39.0983}$ g

= 2.583 moles

Therefore, 101 g of Potassium is equivalent to 2.583 moles of Potassium.

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Step-by-step explanation:

We can define the random variable of interest X as the return from a stock and we know the following conditions:

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And replacing the data given we got:

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$E(X^2) = \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) = (23.4)^2* 0.67 +(-11.9)^2*0.33= 413.5965$

And the variance is given by:

$Var(X) = E(X^2) - [E(X)]^2$

And replacing we got:

$Var(X) = 413.5965 -(11.759)^2 =275.5105$

And finally the deviation would be:

$Sd(X) = \sqrt{275.5105}= 16.599 \%$

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