Question

What is the solution? 45-[5+8y-3(y+3)]= -3(3y-5)-[5(y-1)-2y+6

Answer 1

Answer:

-5

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

45−(5+8y−3(y+3))=−3(3y−5)−(5(y−1)−2y+6)

45+−1(5+8y−3(y+3))=−3(3y−5)+−1(5(y−1)−2y+6)(Distribute the Negative Sign)

45+(−1)(5)+−1(8y)+−1(−3(y+3))=−3(3y−5)+−1(5(y−1))+−1(−2y)+(−1)(6)

45+−5+−8y+3y+9=−3(3y−5)+−5y+5+2y+−6

45+−5+−8y+3y+9=(−3)(3y)+(−3)(−5)+−5y+5+2y+−6(Distribute)

45+−5+−8y+3y+9=−9y+15+−5y+5+2y+−6

(−8y+3y)+(45+−5+9)=(−9y+−5y+2y)+(15+5+−6)(Combine Like Terms)

−5y+49=−12y+14

−5y+49=−12y+14

Step 2: Add 12y to both sides.

−5y+49+12y=−12y+14+12y

7y+49=14

Step 3: Subtract 49 from both sides.

7y+49−49=14−49

7y=−35

Step 4: Divide both sides by 7.

7y

7

=

−35

7

y=−5