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romanna [79]
4 years ago
12

Each leg of a 45 45 90 triangle measures 12cm what is the length of the hypotenuse

Mathematics
2 answers:
artcher [175]4 years ago
7 0
This a right isosceles triangle. Then we can apply Pythagoras:

(hypotenuse)² = 12² +12²

(hypotenuse)² = 144 + 144 = 288

hypotenuse = √288 = 16.97 cm
blondinia [14]4 years ago
7 0
There is one rule for 45-45-90 right triangles.
Hyp = sqrt2 * leg
Hyp = 12sqrt2
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△klm, lm=20 sqrt 3 m∠k=105°, m∠m=30° find: kl and km
Anarel [89]

Answer:

KL =  \frac{20\sqrt{6}}{1+\sqrt{3}} = 17.93

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Explanation:

According to the Law of Sines:

\frac{a}{sinA}=\frac{b}{sinB}= \frac{c}{sinC}

where:

A, B, and C are angles

a, b, and c are the sides opposite to the angles


First of all, let's find m∠L: the sum of the angles of a triangle is 180°, therefore

m∠K + m∠L + m∠M = 180°

m∠L = 180° - m∠K - m∠M

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Now, we can apply the Law of Sines to our case (see picture attached):

\frac{LM}{sinK}=\frac{MK}{sinL}=\frac{KL}{sinM}


Let's solve one side at the time:

\frac{LM}{sinK}=\frac{MK}{sinL}

\frac{20\sqrt{3}}{sin(105)}=\frac{MK}{sin(45)}

MK = \frac{20\sqrt{3} }{sin(105)} \cdot sin(45)

MK = \frac{40\sqrt{3} }{1+\sqrt{3} } = 25.36


Similarily:

\frac{LM}{sinK}=\frac{KL}{sinM}

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KL = \frac{20\sqrt{3} }{sin(105)} \cdot sin(30)

KL = \frac{20\sqrt{6}}{1+\sqrt{3}} = 17.93

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Step-by-step explanation:

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