Answer: Try doing math
Step-by-step explanation: because owo
Let
x: number of regular basketball
y: number of long-distance basket
We have the following system of equations:
2x + 3y = 96
x + y = 45
Solving the system we have
y = 45-x
2x + 3 (45-x) = 96
2x +135 -3x = 96
-x = 96 -135
x = 39
Then,
y = 45-x
y = 45-39
y = 6
answer
were made
regular baskets = 39
long-distance baskets = 6
Answer:
56.3 kilometers per hour
Step-by-step explanation:
We know D = RT
where
D is distance
R is rate (speed)
T is time
Let's Bill's rate be "x". Thus using equation we can write:
D = xt
We know Eugene travelled 21.1 faster than Bill, so Eugene's rate is 21.1 + x. So we can write:
D = (21.1 + x)t
D = 21.1t + xt
Now, putting t = 1 in both since after 1 hour given, we have:
D = x(1)
D = x
and
D = 21.1(1) + x(1)
D = 21.1 + x
We know the sum of both the distance is 133.7, so we can write:
x + 21.1 + x = 133.7
Solving for x:
2x = 133.7 - 21.1
2x = 112.6
x = 112.6 / 2
x = 56.3 km/hr
This is Bill's rate: 56.3 kilometers per hour
Answer:
30
Step-by-step explanation:
because 6 × 5 equals 30 and when you're looking for when something's going to be the same you got to do what your numbers are times each other
Answer:
1036 students
Step-by-step explanation:
Let the number of students at West High be "w" and the number of students at East High be "e"
West High population is 250 FEWER than TWICE of East High, we can write:
w = 2e - 250
Total students in both schools is 2858, so we can write 2nd equation as:
e + w = 2858
We can replace 1st equation in 2nd to get an equation in e, and find "e":
e + w = 2858
e + (2e - 250) = 2858
3e - 250 = 2858
3e = 2858 + 250
3e = 3108
e = 3108/3
e = 1036
Hence,
number of students attending East High School = 1036 students
