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IrinaVladis [17]
4 years ago
10

Can someone explain to me how to get the answer?

Mathematics
1 answer:
kow [346]4 years ago
7 0
Amount = P(1+  \frac{r}{n}) ^{nt}

P is the amount you invested.
r is the interest rate in decimal form (so 6% = 0.06)
n is the number of times a year you are paid interest (semiannually = 2)
nt is the number of payment times you expected (4 years, twice a year = 8 times)
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Which of the following equations could be used to solve for the tenth term of the following sequence?
dmitriy555 [2]

Answer:

A

Step-by-step explanation:

an=a1+(n-1)d

A(10)=15+(n-1)-2

6 0
3 years ago
What is the slope of y = -1 +7?
Rina8888 [55]

Answer:

I think it is 7 but I am not sure

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit
PSYCHO15rus [73]

Question:

Use technology to approximate the solution(s) to the system of equations to the nearest tenth of a unit.

Select all that apply.

f(x)=log x

g(x)=|x-3|

(3.6,0.6)

(-2.6,0.4)

(-3.6,0.6)

(2.6,0.4)

(4.5,-1.5)

Answer:

Option A : (3.6,0.6) is the solution to the system of equations.

Option D: (2.6,0.4) is the solution to the system of equations.

Explanation:

The two equations are f(x)=log x and g(x)=|x-3|

To determine the solution of the system of equations using technology, let us plot the equations in the graphing calculator.

The solution of the system of equations is the intersection of the two lines.

Thus, from the graph, we can see that the two lines f(x) and g(x) intersect at the points (2.587,0.413) and (3.55,0.55)

Rounding off the solution to the nearest tenth, we get,

(2.6,0.4) and (3.6,0.6)

Thus, the solution to the system of equations is (2.6,0.4) and (3.6,0.6)

Hence, Option A and Option D are the correct answers.

3 0
4 years ago
Help what’s the answer ?
iogann1982 [59]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
An article reports "attendance increased 5% this year, to 4948." What was the attendance before the increase? (Round your answer
snow_tiger [21]

Answer: The attendance before the increase was 4712.

Step-by-step explanation:

Let the attendance before the increase be 'x'.

Rate of increment = 5%

so, Attendance after increment becomes

\dfrac{100+5}{100}\times x = 4948\\\\\dfrac{105}{100}\times x=4948\\\\1.05\times x=4948\\\\x=\dfrac{4948}{1.05}\\\\x=4712.38\\\\x=4712

Hence, the attendance before the increase was 4712.

8 0
3 years ago
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