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Vika [28.1K]
4 years ago
5

Please show proof of how u got it ;-; :(

Mathematics
1 answer:
yanalaym [24]4 years ago
8 0

First, divide the the polygon into two quadrilateral.

Then find the area of both quadrilaterals

The area of the small rectangle = 4 x 3 = 12 square feet

The area of the bigger rectangle = (9 - 3) x 14 = 6 x 14 = 84 square feet

Add both areas:

12 + 84 = 96 square feet

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Y is inversely proportional to x, when Y = 7, x = 4.
babymother [125]

Answer:

The given statement  Y = 7, x = 4 is False.

Step-by-step explanation:

We are given:

Y is inversely proportional to x, when Y = 7, x = 4.

We need to tell if the statement is True or False: the constant of proportionality, k, is 20.

Y is inversely proportional to x

We can write it as: y\:\alpha \:\frac{1}{x}\\y=\frac{k}{x}

Now, we need to check when Y=7, x = 4 is true or false

We are given k = 20

Now, I can find value of y, by putting values of k and x in the equation:

y=\frac{k}{x}\\y=\frac{20}{4}\\y=5

When we put x = 4, and k =20, we get Y=5 and not Y=7

So, The given statement  Y = 7, x = 4 is False.

5 0
3 years ago
12:15 = x : 20<br><br> What is X?
e-lub [12.9K]
Answer: x=16

Explanation:
3 0
3 years ago
Find the area (nearest tenth)<br> (not to scale)
enot [183]

Answer:

282.4 sq2

Step-by-step explanation:

15.6 x 18.1 = 282.36

282.36 -> 282.4

6 0
3 years ago
A rectangle has an area of 24 square units and a side length of 234 units. Find the other side length of the rectangle.
zaharov [31]
It would be 24 divided by 234
3 0
3 years ago
a company owner has 20 employees, and plans to give bonuses to 6 of them. How many different sets of employees could receive bon
Leviafan [203]

Answer: 38760

Step-by-step explanation:

Given : The number of employees in the company = 20

The number of employees will be selected by company owner to give bonus = 6

We know that the combination of n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{r!(n-r)!}

Then, the number of different sets of employees could receive bonuses is given by :-

^{20}C_6=\dfrac{20!}{6!(20-6)!}\\\\=\dfrac{20\times29\times18\times17\times16\times15\times14!}{(720)14!}=38760

Hence, the number of different sets of employees could receive bonuses is  38760.

6 0
4 years ago
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