Question

3. The math department needs to buy new textbooks and laptops for their

Answer 1

Let they be x.

Cost of textbooks + laptops cant greater than total amount.

(cost of 1 textbooks * number of textbooks) + (cost of 1 laptop * number of laptops ≤ 6500

(30*116) + (x*439) ≤ 6500

3480 + 439x ≤ 6500

439x ≤ 3020

x ≤ 6.8(approx)

Last natural number is 6, says, they can buy 6 laptops at max.