Given that the domain is all real numbers, what is the limit of the range for the function ƒ(x) = 42x

A composite figure is shown.

VikaD [51]

The surface area of the pyramid is 60 square feet

The surface area of the square prism is 480 square feet

The surface area of the cube is 180 square feet

The total surface area is 720 square feet

<h3>Area of Composite figures</h3>

From the question, we are to calculate the surface area of each part of the composite figure

For the cube

Surface area of a cube is given by

$S = 6l^{2}$

Where $l$ is the length of a side

But only have 5 surfaces of the cube are part of the composite figure

∴ Surface area of the cubic part of the figure = $5l^{2}$

From the given information,

$l = 6 \ feet$

∴ Surface area of the cubic part of the figure = 5 × 6²

Surface area of the cubic part of the figure= 180 square feet

For the square prism

The surface area of a square prism is given by the formula,

$S = 2l^{2} + 4lh$

Where $l$ is the length of the sides and

$h$ is the height

But the <u>square surfaces</u> are not part of the surface of the figure

∴ Surface area of the square prism in the figure = $2l^{2} + 4lh - 2l^{2}$

Surface area of the square prism in the figure = $4lh$

From the given information,

$l = 6 \ feet$

$h = 20 \ feet$

Thus,

Surface area of the square prism part of the figure = 4×6×20

Surface area of the square prism part of the figure = 480 square feet

For the pyramid

The pyramid is a square pyramid

The surface area of a square pyramid is given by

$S = l^{2} + 2l\sqrt{\frac{l^{2} }{4}+h ^{2} }$

Where $l$ is the base length

and $h$ is the height of the prism

But the <u>square base</u> is not part of the surface of the figure

∴ Surface area of the pyramid part of the figure = $l^{2} + 2l\sqrt{\frac{l^{2} }{4}+h^{2} }\ - ( l^{2})$

Surface area of the pyramid part of the figure = $2l\sqrt{\frac{l^{2} }{4}+h^{2} }$

From the given information,

$l = 6 \ feet$

$h = 4 \ feet$

∴ Surface area of the pyramid part of the figure = $2(6)\sqrt{\frac{6^{2} }{4}+4^{2} }$

= $12\sqrt{\frac{36 }{4}+16}$

= $12\sqrt{9+16 }$

= $12\sqrt{25}$

= 12 × 5

= 60 square feet

Hence, the surface area of the pyramid is 60 square feet

Thus,

The total surface area = 180 square feet + 480 square feet + 60 square feet

The total surface area = 720 square feet

Hence, the total surface area is 720 square feet

Learn more on Calculating area of composite figures here: brainly.com/question/13175744

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4 0

2 years ago

Cherry Avenue Park is in the shape of a rectangle. What is the area, in square

wlad13 [49]

Answer: a rectangles area is length x width. You need to find the numbers that represent the length and the width and multiply them

Step-by-step explanation:

7 0

2 years ago

When number can each term of the equation be multiplied by to eliminate the fractions before solving 6-3/4x+1/3=1/2x+5

PolarNik [594]

Answer:

12

Step-by-step explanation:

You need to find the least common denominator (LCD) to all the denominators of the fractions present in the equation. These denominators are (writing them in their prime factor form to make our calculations easier):

$4=2^2\\3=3\\2=2$

Therefore, we need to include a factor of 3, and two factors of 2 ( $2^2$ ) in our least common denominator, so this LCD will be a perfectly divided by all three given denominators, therefore eliminating all fractions in the equation.

Our LCD is = $3*2^2=13*4=12$

6 0

3 years ago

Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?

Alekssandra [29.7K]

<span>First we have to find the sum and the difference of those polynomials- The sum is: ( 3 x^5y - 2 x^3y^4 - 7 xy^3 ) + ( - 8 x^5y + 2 x^3y^4 + xy^3 ) = 3 x^5 - 2 x^3y^4 - 7xy^3 - 8 x^5y + 2 x^3y^4 + xy^3 = - 5 x^5y - 6 xy^3. And the difference: ( 3 x^5y - 2 x^3y^4 - 7 xy^3 ) - ( - 8 x^5y + 2 x^3y^4 + xy^3 ) = 3 x^5y - 2 x^3y^4 - 7 xy^3 + 8 xy^5 - 2 x^3y^4 - xy^3 = 11 xy^5 - 4 x^3y^4 - 8xy^3. The highest exponent in both polynomials is 5. Answer: The degree of the polynomials is 5.</span>

7 0

3 years ago

Read 2 more answers

Pastries made out of filo dough are brushed with either olive oil or butter (but not both). Pastries made out of shortcrust doug

givi [52]

Answer:

3X/20 (option a) of the pastries submitted by Rashid and Mikhail were brushed with butter

Step-by-step explanation:

Rashid pastries (R)

Mikhail pastries (M)

Rashid and Mikhail submitted a total of x pastries

R+M=x (I)

Rashid made 2/3 as many pastries as Mikhail

(2/3)*R=M (II)

Using II in I

R+(2/3)*R=x

(5/3)*R = x

R=(3/5)*x (III)

Using III in I

(3/5)*x+M=x

M=x-(3/5)*x

M=(2/5)*x (IV)

Mikhail filo dough (MF)

Mikhail shortcrust dough (MS)

Rashid filo dough (RF)

Rashid shortcrust dough (RS)

Mikhail used filo dough for all of his pastries

MF=M

MS=0

Rashid used shortcrust dough for all of his pastries

RS=R

RF=0

Filo dough (FD)

FD=RF+MF=0+MF=MF=M (V)

5/8 of the filo dough pastries were brushed with olive oil

pastries brushed with olive oil (OI)

(5/8)*FD=OI

Using V

(5/8)*M=OI

Using IV

(5/8)*(2/5)*x=OI

(1/4)*x=OI (VI)

pastries brushed with butter (B)

Pastries made out of filo dough are brushed with either olive oil or butter (but not both)

FD=OI+B

B=FD-OI

Using V and VI

B= M - (1/4)*x

Using IV

B = (2/5)*x - (1/4)*x

B= (3/20)*x

3X/20 (option a) of the pastries submitted by Rashid and Mikhail were brushed with butter

5 0

3 years ago

Given that the domain is all real numbers, what is the limit of the range for the function ƒ(x) = 42x - 100?