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2 years ago

Help me with 20 please

Mathematics

1 answer:

Murrr4er [49]2 years ago

8 0

24%------360(24% is 360m)

100%-------x (100% is x)

to find x we have too cross multiply

x=100*360/ 24= 1500

hope this helps

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Sam opened a money-market account that pays 3% simple interest. He started the account with $7,000 and made no further deposits.

Verizon [17]

He hold account for 5 years or 5 months. Depending on 3% per year or 3% per month

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2 years ago

Solve the system by graphing. Y=2x-9 y=-2x-1

sattari [20]

Answer:

(2,-5)

Step-by-step explanation:

See attachment

One can also solve this by calculation:

y=2x-9

y=-2x-1

Rearrange either equation to find x. I'll use the first:

y=2x-9

2x = y+9

x = (y+9)/2

Now use this value of x in the second equation:

y = -2x-1

y =-2((y+9)/2)-1

y = (-2y-18)/2)-1

y = -y -9 - 1

2y = -10

y = -5

Now use -5 for y in the rearranged equation:

y = -2x-1

-5 = -2x-1

-2x = -4

x = 2

Solution is (2,-5)

But the question wants a graph solution, which is also fun when you use DESMOS.

4 0

1 year ago

Suppose that a diamond weighs 0.0182 carat.What is that number in expanded form

kvv77 [185]

0.0182=(0 x 1)+ (0/10) + (1/100) + (8/1000) + (2/10000).

7 0

2 years ago

which function has the greatest rate of change? A. y = 7/6x + 2/3 B. y = 7/5x + 7/5 C. y = 6/5x + 11/5 D. y = 5/4x + 15/4

ddd [48]

Answer:

Step-by-step explanation:

In y = mx + b form, the slope can be found in the m position

y = 7/6x + 2/3......slope(m) = 7/6 or 1.167

y = 7/5x + 7/5....slope(m) = 7/5 or 1.4

y = 6/5x + 11/5...slope(m) = 6/5 or 1.2

y = 5/4x + 15/4.....slope(m) = 5/4 or 1.25

so the greatest rate of change would be B. y = 7/5x + 7/5 with a slope of 7/5

3 0

2 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

2 years ago