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IRISSAK [1]
3 years ago
15

James divided 144 ounces of water evenly among 4 containers. One of the containers leaked 8 ounces.

Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Answer:

I dont understand your question rither

Step-by-step explanation:

sorry I would help is I neew

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I know you probably don’t see this but i forgot to do my homework it’s due tomorrow and it’s the called “Volume Unit Study Guide
saw5 [17]

Answer: Make sure all words are spelled correctly.

Try different keywords.

Try more general keywords.

Try fewer keywords.

Step-by-step explanation:

6 0
2 years ago
A coffee business sells a pound of coffee for $ 9.75. Monthly expenses are $ 4,500 plus $ 4.25 for every pound of coffee sold. a
hram777 [196]

Answer:

a. IT = 9.75 * X

b. GT = 4500 + 4.25 * X

c. G = 9.75 * X - 4500 - 4.25 * X

Step-by-step explanation:

With the data of the statement we can get a function. Let X be the number of pounds sold.

to. Monthly income

IT = 9.75 * X

b. Monthly expenses

GT = 4500 + 4.25 * X

c. Monthly Earnings (Monthly Income - Monthly Expenses)

G = 9.75 * X - (4500 + 4.25 * X)

G = 9.75 * X - 4500 - 4.25 * X

4 0
3 years ago
In an isosceles triangle the measure of the angle formed by two congruent sides is 80° what is the measure of each base triangle
shusha [124]

all the bases and sides are all each 80° then

4 0
2 years ago
Find the length of AC<br> Give your answer to 1 decimal place
Fantom [35]

We will use tangent here as we are finding the opposite with the adjacent given.

So we can simply just put this into a calculator:

tan(68°) × 7 cm = AC

tan(68°) × 7 cm = 17.3 cm

3 0
2 years ago
Read 2 more answers
In Exercises 40-43, for what value(s) of k, if any, will the systems have (a) no solution, (b) a unique solution, and (c) infini
svet-max [94.6K]

Answer:

If k = −1 then the system has no solutions.

If k = 2 then the system has infinitely many solutions.

The system cannot have unique solution.

Step-by-step explanation:

We have the following system of equations

x - 2y +3z = 2\\x + y + z = k\\2x - y + 4z = k^2

The augmented matrix is

\left[\begin{array}{cccc}1&-2&3&2\\1&1&1&k\\2&-1&4&k^2\end{array}\right]

The reduction of this matrix to row-echelon form is outlined below.

R_2\rightarrow R_2-R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\2&-1&4&k^2\end{array}\right]

R_3\rightarrow R_3-2R_1

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&3&-2&k^2-4\end{array}\right]

R_3\rightarrow R_3-R_2

\left[\begin{array}{cccc}1&-2&3&2\\0&3&-2&k-2\\0&0&0&k^2-k-2\end{array}\right]

The last row determines, if there are solutions or not. To be consistent, we must have k such that

k^2-k-2=0

\left(k+1\right)\left(k-2\right)=0\\k=-1,\:k=2

Case k = −1:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-1-2\\0&0&0&(-1)^2-(-1)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&-3\\0&0&0&-2\end{array}\right]

If k = −1 then the last equation becomes 0 = −2 which is impossible.Therefore, the system has no solutions.

Case k = 2:

\left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&2-2\\0&0&0&(2)^2-(2)-2\end{array}\right] \rightarrow \left[\begin{array}{ccc|c}1&-2&3&2\\0&3&-2&0\\0&0&0&0\end{array}\right]

This gives the infinite many solution.

5 0
3 years ago
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