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3 years ago

What is the quotient? x-3 divided into 4x2+3x+2

Mathematics

2 answers:

nlexa [21]3 years ago

8 0

Answer:

4x+15

Step-by-step explanation:

Given : $Divisor =x-3$

$Dividend =4x^2+3x+2$

To Find: Quotient

Solution:

$Divisor =x-3$

$Dividend =4x^2+3x+2$

Since we know that

$Dividend = (Divisor \times Quotient) +Remainder$

$4x^2+3x+2 = (x-3 \times 4x) +(15x+2)$

$4x^2+3x+2 = (x-3 \times (4x+15)) +(47)$

Hence the quotient is 4x+15

EastWind [94]3 years ago

5 0

So I just set up a division for this question. I hope this helped and ask for any further help.

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Alborosie

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3 years ago

Suppose on a certain planet that a rare substance known as Raritanium can be found in some of the rocks. A raritanium-detector i

aleksandrvk [35]

Answer:

0.967 = 96.7% probability the rock sample actually contains raritanium

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive reading

Event B: Contains raritanium

Probability of a positive reading:

98% of 13%(positive when there is raritanium).

0.5% of 100-13 = 87%(false positive, positive when there is no raritanium). So

$P(A) = 0.98*0.13 + 0.005*0.87 = 0.13175$

Positive when there is raritanium:

98% of 13%

$P(A) = 0.98*0.13 = 0.1274$

What is the probability the rock sample actually contains raritanium?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1274}{0.13175} = 0.967$

0.967 = 96.7% probability the rock sample actually contains raritanium

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2 years ago

Dry dog food is sold for $9.79 for a 5 pound bag. Dylan bought the bag of dog food to feed his 4 puppies for the next month. If

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Answer:

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3 years ago

Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10

Alenkasestr [34]

Answer: The correct option is (D) SET 4.

Step-by-step explanation: We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

Perpendicular² + Base² = Hypotenuse².

Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.

SET 1 : 14 cm, 5 cm, 6 cm.

We have

$5^2+6^2=25+36=61,\\\\14^2=196.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 2 : 8 in., 12 in., 20 in.

We have

$8^2+12^2=64+144=208,\\\\20^2=400.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 3 : 10 mm, 20 mm, 30 mm.

We have

$10^2+20^2=100+400=500,\\\\30^2=900.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 4 : 12 ft, 16 ft, 20 ft.

We have

$12^2+16^2=144+256=400,\\\\20^2=400.$

Therefore,

Perpendicular² + Base² = Hypotenuse².

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

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3 years ago

Read 2 more answers

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Fittoniya [83]

2 becuase both of those numbers are even.

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