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JulsSmile [24]
2 years ago
9

A telephone pole is 24 feet tall. a 26-foot guy wire is used to stabilize the pole. how far from the base of the telephone pole

should the end of the guy wire be set? (assume that the pole makes a right angle with the ground.)
Mathematics
1 answer:
padilas [110]2 years ago
4 0

Using the Pythagorean Theorem, it is found that the base of the pole should be set 10 feet from the end of the wire.

<h3>What is the Pythagorean Theorem?</h3>

The Pythagorean Theorem relates the length of the legs l_1 and l_2 of a right triangle with the length of the hypotenuse h, according to the following equation:

h^2 = l_1^2 + l_2^2

In this problem, the distance is l_2, while the other measures are l_1 = 24, h = 26, hence:

24^2 + l_2^2 = 26^2

l_2 = \sqrt{26^2 - 24^2}

l_2 = 10

The base of the pole should be set 10 feet from the end of the wire.

More can be learned about the Pythagorean Theorem at brainly.com/question/654982

#SPJ1

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Step-by-step explanation:

Let us assume the weight of peanuts in the mixture   = x kg

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Total weight = (x + y) kg

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Cost of per kg if mixture  = $ 40

So, the cost of (x + y) kg mixture  = (x+y) 40 = 40(x+ y)   ..... (2)

 

The cost of 1 kg of peanuts =  $ 42

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The cost of 1 kg of corns  = $ 36

So cost of y kg of corns  = 36 (y)  = 36 y

So, the total cost of x kg peanuts  + y kg corns =  42 x +  36 y  .... (3)

From (1) and (2), we get:

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Put this in  40(x+ y)  = 42 x +  36 y

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or, 480 - 432 = 6 x

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