1
P(V|A) is not 0.95. It is opposite:
P(A|V)=0.95
From the text we can also conclude, that
P(A|∼V)=0.1
P(B|V)=0.9
P(B|∼V)=0.05
P(V)=0.01
P(∼V)=0.99
What you need to calculate and compare is P(V|A) and P(V|B)
P(V∩A)=P(A)⋅P(V|A)⇒P(V|A)=P(V∩A)P(A)
P(V∩A) means, that Joe has a virus and it is detected, so
P(V∩A)=P(V)⋅P(A|V)=0.01⋅0.95=0.0095
P(A) is sum of two options: "Joe has virus and it is detected" and "Joe has no virus, but it was mistakenly detected", therefore:
P(A)=P(V)⋅P(A|V)+P(∼V)⋅P(A|∼V)=0.01⋅0.95+0.99⋅0.1=0.1085
100,000,000+3,000,000+700,000+20,000+7,000+400+90+5 hope this helps
The distance between those two points would be (8,-3)
2.73972603 or ... you can round to the nearest tenth... 2.7
Answer:
Step-by-step explanation:
<u>Exponential function is:</u>
<u>If we consider the time difference in years as x and the initial population as a, then we get:</u>
<u>Find the value of b:</u>
- b¹⁰ = 675647/617594
- b¹⁰ = 1.09399864636
- b = 1.09399864636^(1/10)
- b = 1.009 (rounded)
<u>The equation we got is:</u>
Here we have y- population after x years since 2010, x - the number of years since 2010 and 1.009 is the population growth rate.
