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choli [55]
4 years ago
10

Not really understanding this, someone help please :)

Mathematics
1 answer:
Nadya [2.5K]4 years ago
5 0

Rearrange the product

(5.91 * 10^(-3)) * (8.7 * 10^10)

as

(5.91 * 8.7) * (10^(-3) * 10^10)

We have 5.91 * 8.7 = 51.417, and 10^(-3) * 10^10 = 10^(10 - 3) = 10^7, so the original product above reduces to

51.417 * 10^7

We can "add" powers of 10 by moving the decimal place to the left:

51.417 = 5.1417 * 10

so that

51.417 * 10^7 = (5.1417 * 10) * 10^7 = 5.1417 * 10^8

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Ben made 5 cups of koolaide. She wants to pour it into glasses that will hold 1/2 a cup. How many glasses will she be able to fi
guapka [62]
She will be able to fill 10 cups with kool-aid because 5 ÷ 1/2 = 10
3 0
3 years ago
Prove that :-<br><br> Cos3A-cosA/sin3A-sinA+cos2A-cos4A/sin4A-sin2A=sinA/cos2Acos3A
ad-work [718]
\dfrac{\cos^3A-\cos A}{\sin^3A-\sin A}+\dfrac{\cos^2A-\cos^4A}{\sin^4A-\sin^2A}=\dfrac{\sin A}{\cos^2A\cos^3A}\\\\L_s=\dfrac{\cos A(\cos^2A-1)}{\sin A(\sin^2A-1)}+\dfrac{\cos^2A(1-\cos^2A)}{\sin^2A(\sin^2A-1)}\\\\=\dfrac{\cos A(-\sin^2A)}{\sin A(-\cos^2A)}+\dfrac{\cos^2A\sin^2A}{\sin^2A(-\cos^2A)}\\\\=\dfrac{\sin A}{\cos A}-1=\tan A-1

R_s=\dfrac{\sin A}{\cos A\cos^4A}=\dfrac{\sin A}{\cos A}\cdot\dfrac{1}{\cos^4A}=\tan A\cdot\dfrac{1}{\cos^4A}=\dfrac{\tan A}{\cos^4A}


\boxed{L_s\neq R_s}
8 0
3 years ago
Please answer correctly !!!!!! Will mark brainliest Answer !!!!!!!!!!!
enyata [817]

Answer:

45 meters

Step-by-step explanation:

graph the equation and find the y-intercept

3 0
3 years ago
-3(7w-3)+8w=-5(w+1) what is the value of w
bogdanovich [222]

Answer:

2

Step-by-step explanation:

Step 1:

- 21w + 9 + 8w = - 5w - 5

Step 2:

- 13w + 9 = - 5w - 5

Step 3:

- 7w + 9 = - 5

Step 4:

- 7w = - 14

Step 5:

14 = 7w

Answer:

w = 2

Hope This Helps :)

6 0
3 years ago
In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is
zheka24 [161]

Answer:

f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

Step-by-step explanation:

Let:

M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y

This is and exact equation, because:

\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}

So, define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)

The solution will be given by:

f(x,y)=C_1

Where C1 is an arbitrary constant

Integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y):

f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}

Substitute into \frac{\partial f(x,y)}{\partial y} =N(x,y)

2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y

Integrate \frac{dg(y)}{dy} with respect to y:

g(y)=\int\ {8y} \, dy =4y^2

Substitute g(y) into f(x,y):

f(x,y)=2x^2+4y^2+2xy

The solution is f(x,y)=C1

f(x,y)=2x^2+4y^2+2xy=C_1

Solving y using quadratic formula:

y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

4 0
4 years ago
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