Answer:
-1960 kJ.
Step-by-step explanation:
C₄H₄O₄(s) + 3O₂(g) ⟶ 2H₂O((ℓ)) + 4CO₂(g) + Energy
There are three energy flows in this reaction.
From combustion + warm water + warm calorimeter = 0
q₁ + q₂ + q₃ = 0
nΔH + mCwΔT + CcalΔT = 0
<em>Data:
</em>
Mass of fumaric acid = 1.1070 g
Mass of water = 1.093 × 10³ g
Cw = 4.184 J·°C⁻¹g⁻¹
T₁ = 21.10 °C
T₂ = 24.52 °C
Ccal = 891.1 J·°C⁻¹
Calculations:
(a) <em>q₁
</em>
n = 1.1070 g × (1 mol/116.07 g)
n = 0.009 537 mol
q₁ = 0.009 537ΔH J
(b) <em>q₂
</em>
ΔT = 24.52 – 21.10
ΔT = 3.42°C
q₂ = 1093 × 4.184 × 3.42
q₂ = 15 640 J
(c) <em>q₃
</em>
q₃ = 891.1 × 3.42
q₃ =3048 J
(d) <em>ΔH</em>
0.009 537ΔH + 15 640 + 3048 = 0
0.009 537ΔH + 18 688 = 0
0.009 537ΔH = -18 688
ΔH = -18 688/0.009 537
ΔH = -1 959 413 J/mol
ΔH = -1960 kJ/mol
This is quite different from the actual value of -1334.70 kJ·mol⁻¹
Answer:
See Explanation
Explanation:
When the balloon is placed above the beaker as described and heating commences, the balloon inflates more. This increased inflation is due to the expansion of the gas in the balloon.
The gas expands because the molecules of gas inside the balloon receive a greater kinetic energy when the temperature was increased hence they move faster and spread out. Recall that temperature is defined as a measure of the average kinetic energy of the molecules in a body.
As the gas in the balloon is heated up, its density decreases. The more the beaker is heated the more the balloon becomes inflated.
When the balloon is removed from the beaker and placed in an ice bath, the balloon shrinks as temperature decreases. This is in conformity with Charles's law.
m(NaOH)=20 g
M(NaOH) = 23+16+1=40 g/mol
20 g*1 mol/40 g= 0.50 mol
0.05 mol NaOH
Answer:
its not actually proven its just a hypothesis because they can't dig that deep because of the pressure
Answer:
1) Ionic compounds are hard and brittle.
2) Ionic compounds have high melting and boiling points.