Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
Solution : Given,
Volume of solution = 500 ml
Molarity of KOH solution = 0.189 M
Molar mass of KOH = 56 g/mole
Formula used :
Now put all the given values in this formula, we get the mass of solute KOH.
Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams
If you cut the cube and keep all the pieces you are causing only physical change
I assume what you're asking about is, how does the temperature changes when we increase water's mass, according the formula for heat ?
Well the formula is :
(where Q is heat, m is mass, c is specific heat and
is change in temperature. So according this formula, increasing mass will increase the substance's heat, but won't effect it's temperature since they are not related. Unless, if you want to keep the substance's heat constant, in that case when you increase it's mass you will have to decrease the temperature
A chemical equation is a short hand expression of a chemical reaction. There aretwo<span> parts to a chemical equation. The reactants are the elements or compounds on the left side of the arrow (-->). The elements and compounds to the right of the arrow are the products.</span>
Answer:
18 grams of water
Explanation:
The Balance Chemical Reaction is as follow,
2 NH₄NO₃ → 2 N₂ + O₂ + 4 H₂O
According to Equation,
160 g (2 moles) NH₄NO₃ produces = 72 g (4 moles) of H₂O
So,
40 g of NH₄NO₃ will produce = X g of H₂O
Solving for X,
X = (40 g × 72 g) ÷ 160 g
X = 18 g of H₂O
<em>Hope This Helps!</em>
