Answer:
The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.
Step-by-step explanation:
The mean sample of the sum of n random variables is
If are indentically distributed and independent, like in the situation of the problem, then the variance of will be the sum of the variances, in other words, it will be n times the variance of .
However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus and as a result, the standard deviation of is the standard deviation of divided by .
Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:
- Restaurants: We have boxes with 9 salmon each, so it will be
- Grocery stores: Each carton has 49 salmon, thus the standard deviation is
- Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is
We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.
Answer:
no
Step-by-step explanation:
Answer:
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Step-by-step explanation:
Given that 5 pounds of rice at a store cost $6.50.
Then 1 pound of rice at a store cost = $6.50/5= $1.3
So the equation for the cost can be written as:
C=1.3P just like we write equation y=mx
Now we have to graph the cost C, vs pounds of rice.
Variable for Pounds of rice is not given so let it be "P"
So let's make a table for the number of pounds (P) and cost (C) we can graph the points from that table to get the final graph.
The Attached graph is the final graph.
3.5 : 5
7 : 10
14 : 20
17.5 : 25
At that rate, she can read 17.5 pages in 25 minuets.
Divide both 7 and 10 by 2, which gets 3.5 and 5
5 * 5 = 25
5 * 3.5 = 17.5
Therefore, in 25 minuets, she can read 17.5 pages.
In which place? Of the value one tens hunderd thousnd