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GrogVix [38]
3 years ago
14

A weight is attached to the end of a spring. Its height after t seconds is given by the equation h(t)=5−2sin((2π(t+1))/7)

Mathematics
1 answer:
taurus [48]3 years ago
3 0

Answer:

실례합니다 ? 이 질문입니까?

Step-by-step explanation:

스프링 끝에 추가 부착되어 있습니다. t초 후의 높이는 h(t)=5−2sin((2π(t+1))/7) 방정식으로 주어집니다. 무게가 처음 최대 높이에 도달하는 시점은 언제입니까? 정확한 답을 주십시오. 오른쪽 ?

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When you purchase an item with a credit card, you might not ever have to pay for it. True False
Sergio039 [100]
False. You get billed by the end of the month the money is “borrowed” money from the bank until you have to pay it all back, if it’s not paid on time you have to pay extra (interest). With debit card your money is taken out immediately.
6 0
2 years ago
What is the volume of a right circular cone if the circumference of the base is 125.6 ft and the height is 75 ft.? Use π=3.14 an
Alex_Xolod [135]

Answer:

The volume of a right circular cone is 31400\ \text{feet}^3.

Step-by-step explanation:

The circumference of the base of a right circular cone is 125.6 ft.

Height of cone is 75 ft.

Circumference of base is :

C=2\pi r, r is radius

r=\dfrac{C}{2\pi}\\\\r=\dfrac{125.6}{2\times 3.14}\\\\r=20\ ft

The volume of a cone is given by :

V=\dfrac{1}{3}\pi r^2 h\\\\V=\dfrac{1}{3}\times 3.14\times (20)^2\times 75\\\\V=31400\ \text{feet}^3

So, the volume of a right circular cone is 31400\ \text{feet}^3.

5 0
3 years ago
Which expression is the same as 5 + 3?
dimaraw [331]

Answer:

8

Step-by-step explanation:

5 + 3 = 8

<em>Hope that helps! </em>

<em>-Sabrina</em>

5 0
2 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
Help! Please! !!!!!!!!!!!!
asambeis [7]

Answer:

?

Step-by-step explanation: what is your question

5 0
2 years ago
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