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3 years ago

How to find the value of x 103-4x=71

Mathematics

1 answer:

jasenka [17]3 years ago

3 0

Answer:

x= 8

Step-by-step explanation:

103 - 4x = 71

You have to isolate -4x by using the subtraction property of equality on 103

103(-103) -4x = 71(-103)

-4x = -32

Use Multiplication Property of Equality for the negative

4x = 32

Divide 4 from both sides

x= 8

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3. Identify the subsets of real numbers that apply to /100/5

Alina [70]

Using number sets, it is found that the correct classification of the number is:

C. rational number, integer, whole number, natural number , real number.

Numbers are classified as:

Whole, which is all positive numbers and zero, also called natural.
Integers, which is the set of whole numbers plus negatives.
Rational, which is the set of integer numbers plus terminating or repeating decimals.
Irrational, which are non terminating decimals.
Real, which are the sum of rational and irrational.

In this problem, the number given is:

$\frac{100}{5} = 20$

Which is a whole(natural) number, thus it is also integer, rational and real, and the correct option is C.

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3 years ago

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3 years ago

In order to help identify baby growth patterns that are unusual, we need to construct a confidence interval of the mean head cir

sukhopar [10]

Answer:

The 99% confidence interval estimate of the mean head circumference of all 2-month-old babies is (40.18cm, 41.02cm).

Step-by-step explanation:

Our sample size is 100.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 100-1 = 99$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-\alpha}{2} = \frac{0.01}{2} = 0.005$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 99 and 0.005 in the t-distribution table, we have $T = 2.626$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{1.6}{\sqrt{100}} = 0.16$

Now, we multiply T and s

$M = Ts = 2.626*0.16 = 0.42$

For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is

$L = 40.6 - 0.42 = 40.18$ cm

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