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pishuonlain [190]
3 years ago
13

Pam is measuring the distance of her journey to school. The distance from her house to the bus stop is 320m, then the bus journe

y is 2.85km. This is how she works out the distance. Fill in the gaps...

Mathematics
1 answer:
enot [183]3 years ago
5 0

Answer with step by step explanation

320m \div 1000 = 0.32km \\

total \:  \:  \: distance \\  = 0.32km + 2.85km \\  = 3.17km

hope this helps you.

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kirill [66]

Answer:

x = 3 and y = 2

or

(3,2)

Step-by-step explanation:

first equation (LCM = 3 x 4 x 5 = 60)

(x+2)/5 - (9-x)/3 = (y - 6)/4

12(x+2) - 20(9-x) = 15(y - 6)

12x + 24 - 180 + 20x = 15y - 90

32x - 15y = -90 - 24 + 180

32x - 15y = 66

second equation:

8(x + 2) - (2x + y) = 2(x + 13)

8x + 16 - 2x - y = 2x + 26

6x - y + 16 = 2x + 26

4x - y = 10

Now you have 2 equations:

4x - y = 10  ---> y = 4x - 10

32x - 15y = 66

Substitute   y = 4x - 10 into 32x - 15y = 66

32x - 15(4x - 10) = 66

32x - 60x + 150 = 66

-28x = -84

    x = 3

    y = 4(3) - 10

    y = 12 - 10

    y = 2

Solutions: x = 3 and y = 2

6 0
3 years ago
Use the diagram to find the measure of angle KHL.
bija089 [108]

Answer:

m∠KHL = 43°

Step-by-step explanation:

From the picture attached,

m∠KHL ≅ m∠GHL [Given in the picture]

Now substituting the values of the angles,

(3x + 1) = (5x - 27)

1 + 27 = 5x - 3x

28 = 2x

14 = x

m∠KHL = (3x + 1)° = (3 × 14) + 1

                             = 42 + 1

                             = 43°

Therefore, measure of ∠KHL = 43°

3 0
3 years ago
In AABC, mZA=x, mZB = 2x +2, and
AnnyKZ [126]

Answer:

x = 29

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Sum the 3 given angles and equate to 180

x + 2x + 2 + 3x + 4 = 180, that is

6x + 6 = 180 ( subtract 6 from both sides )

6x = 174 ( divide both sides by 6 )

x = 29

6 0
3 years ago
Read 2 more answers
Consider the following region R and the vector field F. a. Compute the​ two-dimensional curl of the vector field. b. Evaluate bo
Shalnov [3]

Looks like we're given

\vec F(x,y)=\langle-x,-y\rangle

which in three dimensions could be expressed as

\vec F(x,y)=\langle-x,-y,0\rangle

and this has curl

\mathrm{curl}\vec F=\langle0_y-(-y)_z,-(0_x-(-x)_z),(-y)_x-(-x)_y\rangle=\langle0,0,0\rangle

which confirms the two-dimensional curl is 0.

It also looks like the region R is the disk x^2+y^2\le5. Green's theorem says the integral of \vec F along the boundary of R is equal to the integral of the two-dimensional curl of \vec F over the interior of R:

\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\iint_R\mathrm{curl}\vec F\,\mathrm dA

which we know to be 0, since the curl itself is 0. To verify this, we can parameterize the boundary of R by

\vec r(t)=\langle\sqrt5\cos t,\sqrt5\sin t\rangle\implies\vec r'(t)=\langle-\sqrt5\sin t,\sqrt5\cos t\rangle

\implies\mathrm d\vec r=\vec r'(t)\,\mathrm dt=\sqrt5\langle-\sin t,\cos t\rangle\,\mathrm dt

with 0\le t\le2\pi. Then

\displaystyle\int_{\partial R}\vec F\cdot\mathrm d\vec r=\int_0^{2\pi}\langle-\sqrt5\cos t,-\sqrt5\sin t\rangle\cdot\langle-\sqrt5\sin t,\sqrt5\cos t\rangle\,\mathrm dt

=\displaystyle5\int_0^{2\pi}(\sin t\cos t-\sin t\cos t)\,\mathrm dt=0

7 0
3 years ago
What’s the perimeter of a rectangle with length x and width x-5
MrMuchimi

Answer:

P = 2(x + x - 5) = 2x - 10

Step-by-step explanation:

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