All categories

3 years ago

The point (4,7) is on the graph of y=x^2+c. what is the value of c?

Mathematics

1 answer:

slamgirl [31]3 years ago

7 0

Point is (4,7)
So y = 7 = 4^2 + c
c = 7 - 16
c = -9

You might be interested in

Write an algebraic expression for "12 less than the quotient of 12 and a number z."

tigry1 [53]

12-(12 divided by z) make sure divided by is not in words :)hope it helped

8 0

3 years ago

Read 2 more answers

I need help to solve this question.

LekaFEV [45]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find the domain of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E3-16x%7D" id="TexFormula1" title="\sqrt{x^3

Anon25 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

$f\left(x\right)=\sqrt{x^3-16x}$

We know that the domain of the function is the set of input or arguments for which the function is real and defined.

In other words,

Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

$x^3-16x\ge 0$

as x³ - 16x ≥ 0

$\left(x+4\right)\left(x-4\right)\ge \:0$

Thus, identifying the intervals:

$-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4$

Thus,

The domain of the function f(x) is:

$x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}$

And the Least Value of the domain is -4.

3 0

3 years ago

What is the minimum value of the function y=|x+3|-2 ?

lesya692 [45]

Minimum value of the function is - 2

hope that helps

6 0

3 years ago

Solve the expression 8 x 5 − 12 x one third + 5 using PEMDAS

skelet666 [1.2K]

Answer:41

Step-by-step explanation: Multiplication and division goes first so 8x5=40 12x1/3=4 so 40-4+5 and you do addition and subtraction left to right 40-4=36+5=41

8 0

3 years ago