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2 years ago

Find the missing side.

Mathematics

1 answer:

dexar [7]2 years ago

8 0

Answer:

18.7

Step-by-step explanation:

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Any body <br> want to answer the easyest question in the world and get 17 points<br> what is 2+2=

Ghella [55]

$Your$ $answer$ $would$ $be.$

$4$ $because$ $2+2=4$

$-Yaoii$

7 0

2 years ago

Read 2 more answers

Given f(x)=-3x+3solve for x when f(x)=6

natali 33 [55]

Answer:

x = -1

Step-by-step explanation:

Given: $f(x) = - 3x + 3$

Solve for x, When: $f(x) = 6$

Step by step:

$- 3x + 3 = 6$

$- 3x = 6 - 3$

$- 3x = 3$

$x = 3 \div - 3$

$\boxed{\green{x = - 1}}$

3 0

2 years ago

832x275 to the greatest place value

grandymaker [24]

Answer:

200,000

Step-by-step explanation:

I think this is the answer

5 0

3 years ago

find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B

SashulF [63]

Answer:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3$

$|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{ab}{|a| |b|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{ab}{|a| |b|})$

If we replace we got:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

3 0

2 years ago

Determine if AB¯¯¯¯¯¯¯¯ and CD¯¯¯¯¯¯¯¯ are parallel, perpendicular, or neither. Given: A (−1, 3), B (0, 5), C (2, 1), D (6, −1)

dolphi86 [110]

Answer:

perpendicular

Step-by-step explanation:

To determine if AB and CD are parallel, perpendicular, or neither, we need to get the slope of AB and CD first

Given A (−1, 3), B (0, 5),

Slope Mab = 5-3/0-(-1)

Mab = 2/1

Mab = 2

Slope of AB is 2

Given C (2, 1), D (6, −1)

Slope Mcd = -1-1/6-2

Mcd = -2/4

Mcd = -1/2

Slope of CD is -1/2

Take their product

Mab * Mcd = 2 * -1/2

Mab * Mcd = -1

Since the product of their slope is -1, hence AB and CD are perpendicular

5 0

2 years ago