Question

A sample of CH3OH(g) is placed in the previously evacuated vessel with a pressure of P1 at 600 K. What is the final pressure in the vessel after the reaction is complete and the contents of the vessel are returned to 600 K?

Answer 1

P1

Explanation:

The final pressure in the vessel is the same as that of the start of the reaction. We can use the simplification of the combined gas law to solve this problem.

   The combined gas law is expressed mathematically as;

    $\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }$

P1 is the original pressure

T1 is the initial pressure = 600k

P2 is the final pressure = P2

T2 is the final temperature = 600K

Unknown is the final pressure of the reaction

Input the parameters

   $\frac{P_{1} }{600k} = \frac{P_{2} }{600k }$

 This leaves us with P1 = P2

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Gas law brainly.com/question/9321544

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