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professor190 [17]
3 years ago
6

Sinx=√3/2 and x is less than 90°, calculate tan(90-x)/cos^2x​

Chemistry
1 answer:
dedylja [7]3 years ago
6 0

Answer:

I'm doing this so I can get my number 5 so sorry, but I do not understand that

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A graduated cylinder is filled with 60.0 ml of water. A cube, made of aluminum, is carefully dropped into the cylinder. Aluminum
katen-ka-za [31]

Answer:

65 ml

Explanation:

The aluminum will not float , so it will displace a volume of fluid equal to its volume.

 13.5 gm / 2.7 gm/ml = 5 ml

the new graduated cylinder measurement will be 60 + 5 = 65 ml

3 0
2 years ago
If two atoms are isotopes of the same element, they have the same number of ______ but will have different numbers of ____
kykrilka [37]

Answer:

A.

Explanation:

if it's the same element the protons will always be the same, but have different neutrons, and neutrons is made up of protons and atomic mass, which atomic mass numbers can be calculated different where in return gives different numbers of neutrons.

EX: say the element is carbon, carbon has 6 protons and that won't change, but carbon can have an atomic mass of 12, 13, or 14, etc. so when you make up the neutrons you add protons and atomic mass, 6 + 12 = 18 N

6 + 13 = 19 N

6 + 14 = 20 N

5 0
3 years ago
What is the buffer in the blood? Where does it come from
Andru [333]

When any acidic substance enters the bloodstream, the bicarbonate ions neutralize the hydronium ions forming carbonic acid and water. Carbonic acid is already a component of the buffering system of blood. Thus hydronium ions are removed, preventing the pH of blood from becoming acidic.

6 0
3 years ago
How many grams in 3.2 moles of<br> NH3
Alexxx [7]

Answer:

i. pretty sure its 17.03052

5 0
3 years ago
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g)
monitta

Answer:

The value of the missing equilibrium constant ( of the first equation) is 1.72

Explanation:

First equation: 2A + B ↔ A2B   Kc = TO BE DETERMINED

 ⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]

Second equation: A2B + B ↔ A2B2   Kc= 16.4

⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]

Third equation:  2A + 2B ↔ A2B2     Kc = 28.2

⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²

If we add the first to the second equation

2A + B + B ↔ A2B2   the equilibrium constant Kc will be X(16.4)

But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2)   with Kc = 28.2

So this means: 28.2 = X(16.4)

or X = 28.2/16.4

X = 1.72

with X = Kc of the first equation

The value of the missing equilibrium constant ( of the first equation) is 1.72

7 0
4 years ago
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