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Arada [10]
3 years ago
6

Which lines can you conclude are parallel given that ? Justify your conclusion with a theorem.

Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0
Is there meant to be a picture attached with this?
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The area of a rectangle is 8x3 + 6x2 - 10x. The width of the rectangle is 2x. Find the length of the rectangle.
Sladkaya [172]
2x multiplies to all numbers:
2x x 8x3 = 16x4
2x x 6x2 = 12x3
2x x -10x = -20x2

Answer: 16x4 + 12x³ - 20x²

Hope this helps :)
4 0
3 years ago
Please help ASAP!! I'm really struggling at this problem. Will give 10 points & to the brainliest!
Jlenok [28]

Answer: B

Step-by-step explanation:

To find the result of the dilation, multiply each x and y coordinate by the scale factor, which in this case, is 1.5. I started out with the coordinate P, which had an original coordinate of (-2,1). In this case, I multiplied -2 by 1.5, and 1 by 1.5 to get (-3, 1.5). Since this is multiple choice, the only one with P as (-3, 1.5) is B, so we don't have to check the others.

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Evin is building a tower out of paper cups. In each row (counting from the floor up) there are two less cups than the row below
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What does recursive mean.?
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An angelfish was 1 1/2 inches long when it was bought. Now it is 2 1/3 inches long.
____ [38]

A)

Earlier, The length of the angelfish  = 1 \frac{1}{2} inches

Now, the length of angelfish = 2 \frac{1}{3} inches

We have to determine the grown length of angelfish

=  2 \frac{1}{3} -  1 \frac{1}{2}

= \frac{7}{3}- \frac{3}{2}

LCM of '2' and '3' is '6',

= \frac{14-9}{6}

= \frac{5}{6} inch

Therefore, the angelfish has grown by \frac{5}{6} inch.

B)

We have to determine the increased length of angelfish in feet.

Since 1 inch = \frac{1}{12} foot

So, \frac{5}{6} inch = \frac{5}{6} \times \frac{1}{12} = \frac{5}{72}

= 0.069 foot.

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3 years ago
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In a seventh grade class, 14 out of 30 students are boys. In simplest terms, what is the ratio of the number of boys to the numb
Grace [21]
14 boys : 16 girls

but this would have to be simplified also

7:8
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3 years ago
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