Answer:
- height: 9 chi 6 cun
- width: 2 chi 8 cun
Step-by-step explanation:
The factor-of-ten relationship between the different units means we can combine the numbers in decimal fashion. If 1 unit is 1 zhang, then 1 chi is 0.1 zhang and 1 cun is 0.01 zhang. Hence 6 chi 8 cun is 0.68 zhang.
Let x and y represent the width and height, respectively. In terms of zhang, we have ...
y - x = 0.68
x^2 +y^2 = 1^2
Substituting y = 0.68 +x into the second equation gives ...
x^2 + (x +0.68)^2 = 1
2x^2 +1.36x - 0.5376 = 0 . . . . . eliminate parentheses, subtract 1
Using the quadratic formula, we have ...
x = (-1.36 ±√(1.36^2 -4(2)(-0.5376)))/(2·2) = (-1.36 ±√6.1504)/4
x = 0.28 . . . . . the negative root is of no interest
y = 0.28 +0.68 = 0.96
In units of chi and cun, the dimensions are ...
height: 9 chi 6 cun
width: 2 chi 8 cun
Answer:
y= -3x + 11
Step-by-step explanation:
Slope formula: y^2- y^1 divide by x^2- x^1
y^2 is -1
y^1 is 5
x^2 is 4
x^1 is 2
-1 - 5 = -6
4 - 2 = 2
-6/2 = - 3
Y-intercept: Using the slope and either of the two points, replace the <em>y</em><em>,</em><em> </em><em>m</em><em>,</em><em> </em>and <em>x</em> in y= mx+b.
Using (2, 5)
5= -3(2) + b
5= -6 + b
Add 6 to both sides in order to eliminate -6.
-6 + 6 = 0
5 + 6 = 11
11 = b
Combine your slope-intercept formula:
y= 3x + 11
In pure translation or in roll without slip?
In pure translation, just use Fnet = m*a. Fnet = 7.5 Newtons
In roll without slip it has effectively more inertia than 5 kilograms. The effective inertia can be found as:
m_effective = m + I/r^2
For a uniform solid sphere, I = 2/5*m*r^2
So m_effective = 7/5*m
To make a 5 kg bowling ball accelerate at 1.5 m/s^2 in roll without slip, it requires Fnet = 10.5 Newtons, and this ASSUMES that all forces causing the net force on it have lines of action through its center of mass (most common case).
i hope this is what ur looking for
Answer: b = 17
Step-by-step explanation: The figure shows a triangle which upon closer observation is actually two triangles placed one inside the other. We have triangle QTR (the larger one) and triangle PTS (the smaller one).
The line PS is parallel to line QR, so in effect what we have here are two similar triangles. The ratios of similarity can be derived as
Line QT/line TR = line PT/line TS OR
Line QT/line QR = line PT/line PS.
With these ratios in mind we can now write the following expressions from the similar triangles;
QT = 2b + (2b - 17) and
TR = 16 + 8
TR = 24
Hence,
2b/16 = 2b + (2b - 17)/24
(That is, PT/TS = QT/TR)
2b/16 = (4b - 17)/24
By cross multiplication we now have,
2b(24) = 16(4b - 17)
By expanding the brackets we now have
48b = 64b - 272
By collecting like terms, 64b now moves to the left side of the equation and becomes negative
48b - 64b = -272
-16b = -272
Divide both sides of the equation by -16
b = 17
**Note** A negative number divided by another negative number yields a positive answer.
Answer:
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Step-by-step explanation:
