-5 / 3 + 4k / = -115
1 answer:
Answer:
Step-by-step explanation:
we know That l l = x when x > 0 and l x l = - x when x <0
for the given equation - 5|3 + 4k| = - 115
when 3 + 4k > 0 the equation becomes
-5(3+4k) = - 115
→ -5 · 3 - 5 · 4k = - 115
→- 20k = - 115 + 15 = - 110
→ k = - =
Again when 3 + 4k <0 the equation becomes
-5(-(3+ 4k )) = - 115
→15 + 20k = - 115
→ 20k = - 115 - 15
→ 20k = - 130
⇒ k = - = -
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We want to know the time, <em>t</em>, it takes the ball to reach a height (<em>y</em>) of 0.
We can factor out the GCF first. The largest number that will divide evenly into 16 and 24 is 8. Also, both terms have a <em>t</em>, so we can factor that out as well:
(-16/8 = -2 and 24/8 = 3)
Using the zero product property, we know that either 8t=0 or -2t+3=0. Solving the first equation, we would divide both sides by 8:
8t/8=0/8
t=0
This is at 0 seconds, before the ball is in the air at all.
Solving the second equation, we start by subtracting 3 from both sides:
-2t+3-3=0-3
-2t=-3
Now we divide both sides by -2
-2t/-2=-3/-2
t=1.5
After 1.5 seconds, the ball will hit the ground again.
We can factor out the GCF first. The largest number that will divide evenly into 16 and 24 is 8. Also, both terms have a <em>t</em>, so we can factor that out as well:
Using the zero product property, we know that either 8t=0 or -2t+3=0. Solving the first equation, we would divide both sides by 8:
8t/8=0/8
t=0
This is at 0 seconds, before the ball is in the air at all.
Solving the second equation, we start by subtracting 3 from both sides:
-2t+3-3=0-3
-2t=-3
Now we divide both sides by -2
-2t/-2=-3/-2
t=1.5
After 1.5 seconds, the ball will hit the ground again.