Help! I don’t get it neks

Which is the best to buy? a) 6 shirts for $25.50 b) 4 shirts for $18.00 c) 5 shirts for $21

katrin2010 [14]

Answer:

C. 5 Shirts for $21

Step-by-step explanation:

I conclude this when I calculate the amount of money needed for a singular shirt in every "bundle" by using division.

First I calculated how much you'd have to pay for one shirt in the six-pack collection fo shirts, and I resulted in $4.25 for each shirt. The problem in number form is: 25.50÷6=4.24. By dividing the total with six you result in the singular price of the individual price of each shirt in the pack.

As for the other packs, my calculations resulted in $4.50 for the 4 shirts pack and $4.20 for the 5shirts pack.

5 0

2 years ago

We would like to estimate the proportion of uf students who owns a scooter to within 1% of the truth, with 95% confidence. We be

Varvara68 [4.7K]

Answer: 3458

i hope this work for you

8 0

2 years ago

Please help I’ll give brainliest

Natali [406]

Answer:

3675

Step-by-step explanation:

4 0

3 years ago

Identify the interval on which the quadratic function is positive.

Alenkasestr [34]

Answer:

$\textsf{1. \quad Solution: $1 < x < 4$,\quad Interval notation: $(1, 4)$}$

$\textsf{2. \quad Solution: $-2 < x < 4$,\quad Interval notation: $(-2, 4)$}$

Step-by-step explanation:

<h3>Question 1</h3>

The intervals on which a quadratic function is positive are those intervals where the function is above the x-axis, i.e. where y > 0.

The zeros of the quadratic function are the points at which the parabola crosses the x-axis.

As the given quadratic function has a negative leading coefficient, the parabola opens downwards. Therefore, the interval on which y > 0 is between the zeros.

To find the zeros of the given quadratic function, substitute y = 0 and factor:

$\begin{aligned}y&= 0\\\implies -7x^2+35x-28& = 0\\-7(x^2-5x+4)& = 0\\x^2-5x+4& = 0\\x^2-x-4x+4& = 0\\x(x-1)-4(x-1)&= 0\\(x-1)(x-4)& = 0\end{aligned}$

Apply the zero-product property:

$\implies x-1=0 \implies x=1$

$\implies x-4=0 \implies x=4$

Therefore, the interval on which the function is positive is:

Solution: 1 < x < 4
Interval notation: (1, 4)

<h3>Question 2</h3>

The intervals on which a quadratic function is negative are those intervals where the function is below the x-axis, i.e. where y < 0.

The zeros of the quadratic function are the points at which the parabola crosses the x-axis.

As the given quadratic function has a positive leading coefficient, the parabola opens upwards. Therefore, the interval on which y < 0 is between the zeros.

To find the zeros of the given quadratic function, substitute y = 0 and factor:

$\begin{aligned}y&= 0\\\implies 2x^2-4x-16& = 0\\2(x^2-2x-8)& = 0\\x^2-2x-8& = 0\\x^2-4x+2-8& = 0\\x(x-4)+2(x-4)&= 0\\(x+2)(x-4)& = 0\end{aligned}$

Apply the zero-product property:

$\implies x+2=0 \implies x=-2$

$\implies x-4=0 \implies x=4$

Therefore, the interval on which the function is negative is:

Solution: -2 < x < 4
Interval notation: (-2, 4)

3 0

1 year ago

I don’t understand this math question

pishuonlain [190]

Answer:

S

Step-by-step explanation:

3 0

3 years ago