Hello,
function minmax(int p1,int p2,int p3, int adr_big, int adr_small)
{ int mini=p1,maxi=p1;
if (p1>p2) {mini=p2;}
else {maxi=p2;};
if (p3>maxi) maxi=p3;
if (p3<mini) mini=p3;
*adr_big=maxi;
*adr_small=mini;
};
// main
int a=31,b=5,c=19,big,small;
minmax(a,b,c,&big,&small);
I'm pretty sure you would need to multiply 2/5 by 40.
So, if you multiply 2/5 by 40, you need to turn 40 into a fraction with 1 being the denominator.
2/5 x 40/1 = 80/5
Since the product is an improper fraction, you would simplify it to a whole number.
80/5 = 16.
He can expect to hit it 16 times to get a hole in one.
I hope I am right and have a great day.
Answer:
in what do u need help?
Step-by-step explanation:
