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Alekssandra [29.7K]
3 years ago
9

Use synthetic division to solve (x4 – 1) ÷ (x – 1). What is the quotient?

Mathematics
2 answers:
postnew [5]3 years ago
3 0

Answer:

Simplify, x(3) + x(2) + x + 1

Step-by-step explanation:

bekas [8.4K]3 years ago
3 0

Answer:

x3+x2+x+1

Step-by-step explanation:

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after riding the stationary bike for just 8 minutes, betty had burned 50 calories. how long must she ride if she wants to burn 3
Lyrx [107]

Answer:

52 minutes.

Step-by-step explanation:


4 0
3 years ago
How do you convert 6 2/3 divides by 9 2/3 into a proper fraction
iris [78.8K]

The answer to 6 2/3 divide by 9 2/3 should equal to 20/29.

4 0
3 years ago
The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d
zaharov [31]

Answer:

P(61≤ X≤94) = 49.85%

Step-by-step explanation:

From the given information:

The mean of the bell shaped fluorescent light bulb μ = 61

The standard deviation σ = 11

The objective of this question is to determine the approximate percentage of light bulb replacement requests numbering between 61 and 94 i.e P(61≤ X≤94)

Using the empirical (68-95-99.7)rule ;

At 68% , the data lies between  μ - σ and μ + σ

i.e

61 - 11 and 61 + 11

50 and 72

At  95%, the data lies between  μ - 2σ and μ + 2σ

i.e

61 - 2(11) and 61 + 2(11)

61 - 22 and 61 +22

39   and   83

At 99.7%, the data lies between  μ - 3σ and μ + 3σ

i.e

61 - 3(11) and 61 + 3(11)

61 - 33 and 61 + 33

28   and   94

the probability equivalent to 94 is when  P(28≤ X≤94) =99.7%

This implies that ,

P(28≤ X≤94) + P(61≤ X≤94) = 99.7%

P(28≤ X≤94) = P(61≤ X≤94) = 99.7 %    

This is so because the distribution is symmetric about the mean

P(61≤ X≤94) = 99.7 %/2

P(61≤ X≤94) = 49.85%

5 0
2 years ago
Just need help with question 10 please
anygoal [31]
First place is a

Fifth place is b
3 0
3 years ago
Read 2 more answers
Please help fast
beks73 [17]
You are given that PS ≅ RS as indicated by the single has mark.

You are given that ∠PST ≅ ∠RST as indicated by the single arc.

You know the segment ST is congruent to itself by the reflexive property.

That is, you have two congruent sides and the angle between them, so you can claim the triangles are congruent by the SAS postulate.

Selection C is appropriate.
3 0
3 years ago
Read 2 more answers
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