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Aleksandr-060686 [28]
3 years ago
11

Find the variable of each pair

Mathematics
1 answer:
Lera25 [3.4K]3 years ago
5 0
A. X=4
B. Y= 24, X= 6
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The circumference is 12.56cm and the area is 12.56cm
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40.00 jeans 20% discount
Rudik [331]
If you are asking for the price, then the jeans would cost $32
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If triangle ABC is Congruent with triangle DEF the length of side DE is:
amid [387]
AB is congruent to side DE.

So,

AB= 23 and DE= 23

I hope this helps!
~kaikers
5 0
3 years ago
Read 2 more answers
How many math books and English books did Nicole purchase?
Ksju [112]
Create a system if equations to solve this.

First equation:
25m + 24e = 220

Second equation:
m + e = 9

Then you must solve the second equation for a variable.

Change m + e = 9 to e = 9 - m.

Then substitute (9 - m) for e in the first equation.

So 25m +24e = 220 becomes 25m + 24(9 - m) = 220.

Now you can solve the first equation because the only variable in it is m.

25m + 24(9 - m) = 220 (Original equation)
25m + 216 - 24m = 220 (Distribute)
m + 216 = 220 (Combine like terms)
m = 4 (Simplify)

Now plug in 4 for m in the second equation.

m + e = 9 (Original equation)
(4) + e = 9 (Substitute)
e = 5 (Simplify)

m represents Math Books and e represents English Books, so Nicole purchased 4 Math Books and 5 English Books.
6 0
3 years ago
Debra plans to invest $2,250 for 10 years. She can invest in a savings account that pays 4% simple intrest or a savings account
Diano4ka-milaya [45]

Answer:

\$180.55

Step-by-step explanation:

step 1

<u><em>Simple interest</em></u>

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04

substitute in the formula above

A=2,250(1+0.04*10)

A=2,250(1.4)

A=\$3,150

step 2

<u><em>Interest compounded annually</em></u>

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=10\ years\\ P=\$2,250\\r=4\%=4/100=0.04\\n=1

substitute in the formula above

A=2,250(1+\frac{0.04}{1})^{1*10}  

A=2,250(1.04)^{10}  

A=\$3,330.55

step 3

Find the differences between the two final amounts

A=\$3,330.55-\$3,150=\$180.55

5 0
3 years ago
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