Remember these two combinations: logab=loga+logb, log(a/b)=loga-logb
3logx=logx^3
(1/2)log(x+2)=log(x+2)^(1/2)
2log(z-4)=log(z-4)^2
so the given expression can be combined into log{[(x^3)(z-4)^2]/(x+2)^(1/2)}
They definitely can be positive they can be negative and they can have an absolute value but I would choose they both can be positive and negative
Answer:
The solution set represented by the following graph is:
{x | x∈ R, x < -2}
Step-by-step explanation:
Clearly from the figure we could see that the solution set is to the left of ' -2' and excluding the point '-2' since there is a open circle at -2.
This means that -2 is not included in the set.
Also in interval; form the set of points that belong to the solution set are:
(-∞,-2)
in set-builder form it is written as:
{x | x∈ R, x < -2}
Answer:
27/100
Step-by-step explanation:
27%= 0.27= 27/100 which cannot be reduced
