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3 years ago

6

Ken has 7 baseballs. Each baseball weighs 0.3 pound . Ken wants to use this model to find the total weight of the baseballs. Eac

h hundredths block in the model represents 1 whole .

2 answers:

stira [4]3 years ago

6 0

Answer:

14

Step-by-step explanation:

creativ13 [48]3 years ago

6 0

14 balls and try your best

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Can you please help will give brainliest please

Brrunno [24]

The perimeter is 18. Which would be the distance.

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3 years ago

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Let w = 4. Enter >, <, or = to compare the expressions. 3w² + 1 10w + 8

Svetach [21]

Answer: ≥ without the line on the bottom.

Step-by-step explanation:

I am assuming the expression you are talking about are

$3w^{2} +1$ and $10w+8$ .

If we were to replace w with 4 and calculate, we will find the answer:

$3*4^{2} +1=3*16+1=48+1=49$

$10*4+8=40+8=48$

Since the first expression, $3w^{2} +1$ , is bigger than the second expression, the correct symbol to use is ≥ without the line on the bottom.

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3 years ago

Im not sure where to start with this one...<br>

Nina [5.8K]

The volume of a cube is side length cubed (s^3)
So if you know the volume then take the cube root of 1/512... which is 1/8

So each side of the cube is 1/8.

There are 6 congruent sides on a cube (picture a “dice”). Do the area of each side would be (1/8)(1/8)= 1/64 then multiply that area by 6 and reduce ... you get 6/64 = 3/32 for the surface area

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4 years ago

Each scarf requires. Meters of yarn, and each beanie requires meters

stiv31 [10]

1 scarf = 6m of yarn

1 beanie = 2m of yarn

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3 years ago

Solve 12^x^2+5x-4 = 12^2x+6

faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

$x^{2}+5 x-4=2 x+6$

$x^{2}+5 x-2 x-4-6=0$

$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For $a x^{2}+b x+c=0$ , the values of x which are the solutions of the equation are given by:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Where, a = 1, b = 3 and c = -10

$x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}$

$x=\frac{-3 \pm \sqrt{9+40}}{2}$

$x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}$

So, the solutions for ‘x’ are

$x=\frac{-3+7}{2}=\frac{4}{2}=2$

$x=\frac{-3-7}{2}=\frac{-10}{2}=-5$

The solutions for ‘x’ are 2 and -5

6 0

3 years ago

Read 2 more answers