I hope this helps you
Can anybody solve this problem?
1 answer:
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Answer:
Step-by-step explanation:
A vector perpendicular to the plane ax+by+cz+d=0 is of the form .
So, a vector perpendicular to the plane x − y + 2z = 7 is .
The parametric equations of a line through the point and parallel to the vector
are as follows:
Put and
Therefore,
xy-plane:
Put z = 0 ⇒ t = -2 ⇒x = - 1 , y = 6
So, at point (-1,6,0)
yz-plane:
Put x = 0 ⇒ t = -1 ⇒ y = 5, z =2
So, at point (0,5,2)
xz-plane:
Put y = 0 ⇒ t = 4 ⇒ x = 5, z = 12
So, at point (5,0,12)