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mixas84 [53]
2 years ago
10

Mr. Clinton went to the lumber company. He bought 6 boards at a cost of $4.12 per board and 5 pounds of nails at $0.78 per pound

. What was the total cost for these items (not including tax)?
Mathematics
2 answers:
morpeh [17]2 years ago
6 0

Answer:

djjdjdjdjdjdjdjdjdidi

Contact [7]2 years ago
5 0

$28.62 not including tax.

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En el estante de un negocio hay 2 tipos de tarros de la misma mermelada y marca. El tarro más alto tiene el doble de altura que
Ipatiy [6.2K]

Answer:

tarro corto

Step-by-step explanation:

Aquí tenemos que comprar el frasco que tiene el menor costo por volumen.

h_1 = Altura del frasco corto

h_2 = La altura del frasco alto es el doble que el del frasco corto. = 2h_1

d_1 = Diámetro del frasco corto

d_2 = El diámetro del frasco alto es la mitad del frasco corto = \dfrac{1}{2}d_1

El volumen de un cilindro es \pi \dfrac{d^2}{4}h

La razón de los volúmenes de los frascos es

\dfrac{V_1}{V_2}=\dfrac{\pi\dfrac{d_1^2}{4}h_1}{\pi\dfrac{d_2^2}{4}h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{d_2^2h_2}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{(\dfrac{1}{2}d_1)^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{d_1^2h_1}{\dfrac{1}{4}d_1^22h_1}\\\Rightarrow \dfrac{V_1}{V_2}=\dfrac{1}{\dfrac{1}{2}}\\\Rightarrow \dfrac{V_1}{V_2}=2\\\Rightarrow V_1=2V_2

El costo del frasco corto por unidad de volumen es

\dfrac{8000}{V_1}=\dfrac{8000}{2V_2}=\dfrac{4000}{V_2}

El costo del frasco alto por unidad de volumen es

\dfrac{4500}{V_2}=\dfrac{4500}{V_2}

\dfrac{4000}{V_2}

Entonces, el costo del frasco corto por unidad de volumen es menor que el costo por unidad de volumen del frasco alto.

Por lo tanto, deberíamos tomar el frasco corto.

5 0
2 years ago
What is -5 divided by 2
amm1812

-2.5 is the answer.

Hope it helps.


5 0
2 years ago
Read 2 more answers
you have a piece of wood that is 72 inches long u cut the wood into three pieces the second piece is 6 inches longer than the fi
tangare [24]

Let

x---------> the length of the first piece

y---------> the length of the second piece

z---------> the length of the third piece

we know that

x+y+z=72 -------> equation 1

y=x+6 -----> solve for x

x=y-6 -------> equation 2

z=6+y -------> equation 3

substitute equation 2 and equation 3 in equation 1

[y-6]+y+[6+y]=72

3y=72

y=(72/3)=24 in

<u>Find the value of x</u>

x=y-6 -------> equation 2

x=24-6=18 in

<u>Find the value of z</u>

z=6+y -------> equation 3

z=6+24=30 in

therefore

<u>the answer is</u>

the length of the first piece is 18 in

the length of the second piece 24 in

the length of the third piece is 30 in

7 0
3 years ago
Sylvia has three pet gerbils. if two of her gerbils each has two babies every two months, how many babies will the gerbils has a
katen-ka-za [31]

Answer:

They will have 24 babies in one year

Step-by-step explanation:

All you need to do is add 6 babies every two months starting in January. Include January as the gerbils having their first 6 babies. Every 2 months includes 4 months out of the year. 6*4 = 24 babies.

3 0
3 years ago
Read 2 more answers
The lengths of a certain species of fish are approximately normally distributed with a given mean ll and standard
RoseWind [281]
How are you? Ok so It probably B but I’m not sure so just wait a few minutes till someone else answers because I’m not sure
5 0
2 years ago
Read 2 more answers
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